Kivy从屏幕管理器访问类属性

时间:2020-07-15 02:28:08

标签: python kivy kivy-language

我正在使用python和kivy制作一个简单的应用程序,但是当我为我的应用程序创建多个屏幕时,我无法访问某些类的类属性。

使用屏幕管理器访问方法时遇到问题。

main.py

from kivy.app import App
from kivy.lang import Builder
from kivy.uix.screenmanager import ScreenManager, Screen
from kivy.uix.widget import Widget


class MyGame(Widget):
    def __init__(self, **kwargs):
        super(MyGame, self).__init__(**kwargs)

    def print_a_word(self):
        print('a word')

class OptionWindow(Screen):
    pass


class SecondWindow(Screen):
    pass


class WindowManager(ScreenManager):
    pass

kv = Builder.load_file('screen_manager.kv')

class MyMainApp(App):
    def build(self):
        return kv

if __name__ == "__main__":
    MyMainApp().run()

kivy文件(screen_manager.kv)

#:kivy 2.0.0
# File name: screen_manager.kv
#: import MyGame Widget

WindowManager:

    OptionWindow:
    SecondWindow:

<OptionWindow>:
    name: "main"

    GridLayout:
        cols:1
        canvas.before:
            Color:
                rgba: 1, 1, 1, 1
            Rectangle:
                pos: 0, 0
                size: root.width, root.height
        GridLayout:
            rows: 5
            padding: 50, 50
            spacing: 20, 20
            OptionBtn:
                text: 'Americas'
                on_release:
                    app.root.current = "second"
                    root.manager.transition.direction = "left"



<SecondWindow>:
    name: "second"
    MyGame
    Button:
        on_press: root.MyGame.print_a_word()


<OptionBtn@Button>
    background_normal: 'Images/Other/white.png'
    color: 0, 0, 0, 1
    font_size: 20
    canvas.after:
        Color:
            rgba: 0, 0, 0, 1
        Line:
            rectangle: self.x, self.y, self.size[0], self.size[1]

一切正常,直到我按下第二个窗口的按钮。我无法从MyGame(Widget)访问该方法。我得到'SecondWindow' object has no attribute 'MyGame'

这是一个较大问题的一部分,因为我制作此文件来解决我的原始问题是... 我有一个很大的程序,其中有两个文件main.py和my.kv,我想添加屏幕。在这个main.py中,所有内容都定义了一个从Widget继承的类,并且build方法返回该类的实例。这就是为什么我从上面制作文件的原因……是为了了解如何从Widget类进行访问。谢谢

1 个答案:

答案 0 :(得分:0)

在这里,我修复了示例代码,现在可以访问和执行MyGame()对象中的print_my_word()方法,这足以为您提供帮助。

仅kv文件需要更改:

使用包含而不是在“ MyGame”对象中导入:
#:包括MyGame

对象中实例化它。

为其添加了一个ID,以便可以访问它。

three = [word[2] for word in words]

好吧,下面的下一部分是更新,可以在第二条评论中回答您的问题。

main.py

WindowManager:

    OptionWindow:
    SecondWindow:

<OptionWindow>:
    name: "main"

    GridLayout:
        cols:1
        canvas.before:
            Color:
                rgba: 1, 1, 1, 1
            Rectangle:
                pos: 0, 0
                size: root.width, root.height
        GridLayout:
            rows: 5
            padding: 50, 50
            spacing: 20, 20
            OptionBtn:
                text: 'Americas'
                on_release:
                    app.root.current = "second"
                    root.manager.transition.direction = "left"



<SecondWindow>:
    name: "second"
    MyGame:
        id: my_game
    Button:
        on_press: my_game.print_a_word()


<OptionBtn@Button>
    background_normal: 'Images/Other/white.png'
    color: 0, 0, 0, 1
    font_size: 20
    canvas.after:
        Color:
            rgba: 0, 0, 0, 1
        Line:
            rectangle: self.x, self.y, self.size[0], self.size[1]

screen_manager.kv

from kivy.app import App
from kivy.lang import Builder
from kivy.uix.screenmanager import ScreenManager, Screen
from kivy.uix.widget import Widget


class MyGame(Widget):
    def __init__(self, **kwargs):
        super(MyGame, self).__init__(**kwargs)

    def print_a_word(self):
        print('My Game: print method')

class OptionWindow(Screen):
    pass


class SecondWindow(Screen):
    pass


class WindowManager(ScreenManager):
    pass

kv = Builder.load_file('screen_manager.kv')

class MyMainApp(App):
    def build(self):
        self.my_game = MyGame()  # <-- instantiated MyGame in the Main class to access it from any where
        return kv

if __name__ == "__main__":
    MyMainApp().run()