由于后退键会破坏我的应用程序并且所有数据都将丢失,我需要拦截它以询问用户这是否真的是他想要的。
我想到了以下结构:
@Override
public boolean onKeyDown(int keyCode, KeyEvent event)
{
if (keyCode == KeyEvent.KEYCODE_BACK && event.getRepeatCount() == 0)
{
// ask user if he really wants to exit
// no --> return true;
// yes --> return super.onKeyDown(keyCode, event);
//manually entering either of the return values works fine
}
return super.onKeyDown(keyCode, event);
}
我想通过警告对话框实现“询问用户”这篇文章。我的问题是现在显示警告对话框但是onKeyDown方法在显示警告对话框时运行到结束,并且在警告对话框中我不知道如何告诉系统传递正确的返回值。
我想到的完整代码是
@Override
public boolean onKeyDown(int keyCode, KeyEvent event)
{
if (keyCode == KeyEvent.KEYCODE_BACK && event.getRepeatCount() == 0)
{
alertDialog = new AlertDialog.Builder(this).create();
alertDialog.setTitle("Tile");
alertDialog.setMessage("data lost, are you sure?");
alertDialog.setButton(-1, getString(R.string.yes), new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int which)
{
return;
//I only can return without a boolean value here. }
});
alertDialog.setButton(-2, getString(R.string.no), new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int which)
{
return;
}
});
alertDialog.show();
}
return super.onKeyDown(keyCode, event);
}
谢谢,A。
答案 0 :(得分:3)
当用户按下时,会出现对话框。
现在已经处理了onKeyDown,所以你返回true。
您的对话框现在正在显示,
当你按是时你想模仿后退按钮finish();确实
当您按否时,您只需关闭对话框并继续活动
你会想要这个:
@Override
public boolean onKeyDown(int keyCode, KeyEvent event)
{
if (keyCode == KeyEvent.KEYCODE_BACK && event.getRepeatCount() == 0)
{
alertDialog = new AlertDialog.Builder(this).create();
alertDialog.setTitle("Tile");
alertDialog.setMessage("data lost, are you sure?");
alertDialog.setButton(-1, getString(R.string.yes), new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int which)
{
finish(); // or yourContext.finish();
//I only can return without a boolean value here.
}
});
alertDialog.setButton(-2, getString(R.string.no), new DialogInterface.OnClickListener()
{
@Override
public void onClick(DialogInterface dialog, int which)
{
// do nothing dialog will dismiss
}
});
alertDialog.show();
return true; //meaning you've dealt with the keyevent
}
return super.onKeyDown(keyCode, event);
}
答案 1 :(得分:0)
alertDialog.show();应该在没有按钮的onClick上调用