如何将两个列表明智地组合成一个列表元素？

Question

例如，如果我有：

A = [1, 2, 3]` & `B = [4, 5, 6]

我想拥有

C = [[1, 4], [2, 5], [3, 6]]

Answer 1

您可以使用元组和zip满足此要求。

示例代码-

>>> a = [1,2,3]
>>> b = [4,5,6]

>>> c = tuple(zip(a,b))
>>> print(c)
((1, 4), (2, 5), (3, 6))

Answer 2

为此有一个名为zip的内置函数：

[list(ab) for ab in zip(a,b)]

或使用地图和邮政编码：

list(map(list, zip(a,b)))

两次返回：

[[1, 4], [2, 5], [3, 6]]

Answer 3

您可以这样做：

a = [1,2,3]
b = [4,5,6]
c = [list(x) for x in zip(a, b)]

Answer 4

In [110]: A = [1,2,3]

In [111]: B = [4,5,6]

In [112]: list(zip(A,B))
Out[112]: [(1, 4), (2, 5), (3, 6)]