Question

如何在Codeigniter查询功能中获取两个日期之间的值？这是我的模型和示例代码。

function get_promo() {
    $today = date('Y-m-d');
    $query = $this->db->query('SELECT FROM tbl_event WHERE event_id = $id AND event_startdate <= $today
    AND event_enddate >= $today');
    return $query;
}

但它不起作用，这是我得到的错误

A Database Error Occurred

Error Number: 1064

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM tbl_event WHERE event_id = 36 AND event_startdate <= 2011-06-09 ' at line 1

SELECT FROM tbl_event WHERE event_id = 36 AND event_startdate <= 2011-06-09 AND event_enddate >= 2011-06-09

Filename: C:\xampp\htdocs\hotel\system\database\DB_driver.php

Line Number: 330

Answer 1

我认为您需要在约会时间（即“2011-06-08”）。试试这个

function get_promo() {
    $today = date('Y-m-d');  
    $query = $this->db->query(
        "SELECT FROM tbl_event WHERE event_id = {$id} AND event_startdate <= '{$today}'
        AND event_enddate >= '{$today}'");
    return $query;
}

如果您的列event_startdate和event_enddate是DATETIME类型，但您只对日期部分感兴趣，可以执行`DATE（event_enddate）来提取日期部分

Answer 2

我认为您需要使用date_format（），此链接中的更多信息http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format。

试试这段代码：

$today = date('Y-m-d');
$query = $this->db->query("SELECT FROM tbl_event WHERE event_id = $id AND DATE_FORMAT(event_startdate ,'%Y-%m-%d') >= DATE_FORMAT($today ,'%Y-%m-%d') AND DATE_FORMAT(event_enddate ,'%Y-%m-%d') <= DATE_FORMAT($today ,'%Y-%m-%d')");

Answer 3

查看错误，似乎您的查询未正确转义。添加单引号或双引号来修复它。检查@danneth的答案。使用简单安全的Query Binding或更多使用Active Record。以下是基于您的代码的绑定和活动记录的示例。

查询绑定示例

    $today = date('Y-m-d');
    $sql = 'SELECT 
  * 
FROM
  tbl_event 
WHERE event_id = ? 
  AND event_startdate <= ? 
  AND event_enddate >= ?';
    $query = $this->db->query($sql, array($id, $today, $today));
return $query;

有效记录示例

$query = $this->db
        ->select('*')->from('tbl_event')
        ->where(array(
            'event_id' => $id,
            'event_startdate <= ' => $today,
            'event_enddate >= ' => $today
        ))
        ->get();
return $query;

附加->result()或->result_array()等以获取对象或数组中的结果。查看Codeigniter Database User Guide了解更多信息。快乐的编码！

Answer 4

您需要使用正确的格式。试试这个：

$todaystart = date('Y-m-d 00:00:00');  
$todayend = date('Y-m-d 23:59:59');  
       $query = $this->db->query('SELECT FROM tbl_event WHERE event_id = $id AND event_startdate <= ? AND event_enddate >= ?', array($todaystart, $todayend));

编辑：您的查询错误。这样做：

$todaystart = date('Y-m-d 00:00:00');  
$todayend = date('Y-m-d 23:59:59');  
       $query = $this->db->query('SELECT * FROM tbl_event WHERE event_id = $id AND event_startdate <= ? AND event_enddate >= ?', array($todaystart, $todayend));

Answer 5

$this->db->where('date_start <=',date('Y-m-d'));
$this->db->where('date_end >=',date('Y-m-d'));
$query = $this->db->get('table');

比较Codeigniter和MySQL中的两个日期

5 个答案: