Question

如何使用python请求库发送以下请求？

请求：

我尝试过

with requests.Session() as session:
    // Some login action

    url = f'http://somewebsite.com/lib/ajax/service.php?key={key}&info=get_enrolled'
    json_data = {
        "index": 0,
        "methodname": "get_enrolled",
        // And so on, from Request Body
    }

    r = session.post(url, json=json_data)

但是它没有给出我想要的输出。

Answer 1

1。定义POST请求方法

import urllib3
import urllib.parse

def request_with_url(url_str, parameters=None):
    """
    https://urllib3.readthedocs.io/en/latest/user-guide.html
    """
    http = urllib3.PoolManager()
    response = http.request("POST",
                            url_str, 
                            headers={ 
                                'Content-Type' : 'application/json' 
                            },
                            body=parameters)
    resp_data = str(response.data, encoding="utf-8")
    return resp_data

2。使用您的特定网址和参数调用函数

json_data = {
        "index": 0,
        "methodname": "get_enrolled",
        // And so on, from Request Body
    }
key = "123456"
url = "http://somewebsite.com/lib/ajax/service.php?key={0}&info=get_enrolled".format(key)

request_with_url(url, json_data)

Answer 2

没有更多信息，您想要什么，从哪个URL很难获得帮助。但是，请尝试将带有用户代理的标题添加到帖子中。可能需要更多的标头，但是User-Agent是经常需要的标头。

with requests.Session() as session:
    // Some login action

    url = f'http://somewebsite.com/lib/ajax/service.php?key={key}&info=get_enrolled'
    json_data = {
        "index": 0,
        "methodname": "get_enrolled",
        // And so on, from Request Body
    }
    headers = {'User-Agent': 'Mozilla/5.0'}
    r = session.post(url, json=json_data, headers=headers)

如何使用python请求库发送此请求

2 个答案: