我有一个如下表,存储在字典中:
字典看起来像这样
d = {
'A': ['45', '70', '5', '88', '93', '79', '87', '69'],
'B': ['99', '18', '91', '3', '92', '2', '67', '15'],
'C': ['199200128', '889172415', '221388292', '199200128', '889172415', '889172415', '199200128', '221388292'],
'D': ['10:27:05', '07:10:29', '17:04:48', '10:25:42', '07:11:18', '07:11:37', '10:38:11', '17:08:55'],
'E': ['73', '6', '95', '21', '29', '15', '99', '9']
}
我想根据从最低到最高的小时数对字典进行排序,并对A,B和E列求和,C列中的值与下图中的值相同(下图中A,B和E的总和在红色):
然后,结果字典将如下所示:
{
'A': ['70', '93', '79', '242', '88', '45', '133', '87', '5', '69', '161'],
'B': ['18', '92', '2', '112', '3', '99', '102', '67', '91', '15', '173'],
'C': ['889172415', '889172415', '889172415', '', '199200128', '199200128', '', '199200128', '221388292', '221388292', ''],
'D': ['07:10:29', '07:11:18', '07:11:37', '', '10:25:42', '10:27:05', '', '10:38:11', '17:04:48', '17:08:55', ''],
'E': ['6', '29', '15', '50', '21', '73', '94', '99', '95', '9', '203']
}
我目前正在尝试使用此代码对输入字典进行排序,但似乎对我不起作用。
>>> sorted(d.items(), key=lambda e: e[1][4])
[
('D', ['10:27:05', '07:10:29', '17:04:48', '10:25:42', '07:11:18', '07:11:37', '10:38:11', '17:08:55']),
('E', ['73', '6', '95', '21', '29', '15', '99', '9']),
('C', ['199200128', '889172415', '221388292', '199200128', '889172415', '889172415', '199200128', '221388292']),
('B', ['99', '18', '91', '3', '92', '2', '67', '15']),
('A', ['45', '70', '5', '88', '93', '79', '87', '69'])
]
>>>
可能有人对此提供帮助。谢谢
答案 0 :(得分:1)
您允许使用熊猫来解决此任务吗? 如果是,那么您可以将数据转换为
pd.DataFrame
对象
data = pd.DataFrame.from_dict(dictionary, orient = 'columns')
data = data.sort_values(by =„D”)
然后使用
再次返回字典_dict = data.to_dict()