Question

您好我在创建简单表时阻止请帮帮我使用ubuntu 11.04 - PostgreSQL 8.4.8 用phppgadmin我得到这段代码：

CREATE TABLE users 
(
  id                SERIAL,
  username          CHARACTER VARYING(255),
  PASSWORD           CHARACTER VARYING(255),
  etat              INTEGER(1),
  avatar            CHARACTER VARYING(255),
  description       text,
  email             CHARACTER VARYING(255),
  website           CHARACTER VARYING(255),
  country           CHARACTER VARYING(255),
  location          CHARACTER VARYING(255),
  nb_upload         INTEGER,
  sexe              CHARACTER VARYING(25),
  group_id          INTEGER,
  created           DATE,
  modified          DATE,
  enable_mail       INTEGER(1),
  enable_location   INTEGER(1),
  facebook_id       BIGINT,
  PRIMARY KEY (id)
)

但每次执行时都会返回此错误：

错误：语法错误在或附近“（” 第1行：...“密码”字符变化（255），“etat”整数（1），“avat ...

感谢

Answer 1

integer(1)在PostgreSQL中不是有效的数据类型。正确的名称是integer

有关所有可用类型的完整列表，请参阅手册：

http://www.postgresql.org/docs/current/static/datatype.html

编辑：

如果要存储存储true / false的“标志”，请使用boolean数据类型。

Answer 2

CREATE TABLE "public"."users" ("id" SERIAL, "username" character varying(255), "password" character varying(255), "etat" integer, "avatar" character varying(255), "description" text, "email" character varying(255), "website" character varying(255), "country" character varying(255), "location" character varying(255), "nb_upload" integer, "sexe" character varying(25), "group_id" integer, "created" date, "modified" date, "enable_mail" integer, "enable_location" integer, "facebook_id" bigint, PRIMARY KEY ("id"))

这应该对你有用）你的意思是整数（1）？）

在postgresql上创建一个表

2 个答案: