Question

我正在尝试根据第二个数组文本过滤第一个数组，但是我没有得到如何将计数过滤器从第二个数组更新为第一个数组。

第一个数组：

resolve()

第二个数组：

const request = require('request');
const process = require('process');

const args = process.argv[2];
let offset = 0;
let flag = false;
const clientID = 'agdn5682y521syqhwkdrqmw7ho6v7d';



function getGameInfo(args, offset, clientID){
    return new Promise(function(resolve, reject){
      const options = {
      method: 'GET',
      url: `https://api.twitch.tv/kraken/streams/?game=${args}&limit=100&offset=${offset}`,
      headers: {
        'Client-ID': clientID,
        'Accept': 'application / vnd.twitchtv.v5 + json'
      }
    }
        request(options, function (err, response, body) {
            if (err) return reject(err);
            try {
                resolve(JSON.parse(body));
            } catch(e) {
                reject(e);
            }
        });
    });
}

getGameInfo("pubg", offset, clientID).then(function(val) {
    console.log(val);
}).catch(function(err) {
    console.log(err);
});

代码：

var firstArray =[{text:"India",count:1,checked:true},
{text:"America",count:2,checked:false},
{text:"Uk",count:1,checked:true}];

我当前得到的结果：

var secondArray=[
{text:"India",count:1,checked:false},
{text:"America",count:1,checked:false},
{text:"Uk",count:1,checked:false}
];

我想要得到的结果如下：

var result=firstArray.filter(o1 => secondArray.some(o2 => o1.text === o2.text));

感谢您的帮助！

Answer 1

您可以映射第一个数组，然后从第二个数组中选择计数

var firstArray = [
  { text: "India", count: 1, checked: true },
  { text: "America", count: 2, checked: false },
  { text: "Uk", count: 1, checked: true },
];

var secondArray = [
  { text: "India", count: 1, checked: false },
  { text: "America", count: 1, checked: false },
  { text: "Uk", count: 1, checked: false },
];

firstArray
  .map((x) => {
    const tmp = secondArray.find((y) => y.text === x.text);
    return tmp ? { ...x, count: tmp.count } : null
})
  .filter(Boolean);

Answer 2

可能的解决方案如下

var firstArray = [{
    text: "India",
    count: 1,
    checked: true
  },
  {
    text: "America",
    count: 2,
    checked: false
  },
  {
    text: "Uk",
    count: 1,
    checked: true
  }
];

var secondArray = [{
    text: "India",
    count: 1,
    checked: false
  },
  {
    text: "America",
    count: 1,
    checked: false
  },
  {
    text: "Uk",
    count: 1,
    checked: false
  }
];

var result = firstArray.map(o1 => {
  const o2 = secondArray.find(o2 => o1.text === o2.text);
  if (!o2) return;
  return { ...o1,
    count: o2.count
  }
}).filter(o1 => !!o1);

console.log(result)

Answer 3

此解决方案将合并两个数组以获得期望的结果（从答案中推论得出）

var firstArray =[{text:"India",count:1,checked:true},
{text:"America",count:2,checked:false},
{text:"Uk",count:1,checked:true}];

var secondArray=[
{text:"India",count:1,checked:false},
{text:"America",count:1,checked:false},
{text:"Uk",count:1,checked:false}
];

const newArray = firstArray.map((el1) => {
  let sameElList = secondArray.filter((el2) => el2.text === el1.text);
  let sameEl = sameElList.length > 0 && sameElList.pop();
  if(!sameEl){
    return el1;
  }
  el1.count = Math.min(el1.count, sameEl.count);
  el1.checked = el1.checked || sameEl.checked;
  return el1;
 });
 
 console.log(newArray);

我正在尝试从2数组中检索结果

3 个答案: