学习RxJava,因此希望获得任何建议。
计算准备就绪时需要接收对象,因此我在模型方法中设置了PublishSubject
:
public PublishSubject<BaseUnit> exec(int inputNumber) {
if (unitList.size() > 0) {
for (BaseUnit unit : unitList) {
unit.setInProgress();
}
}
PublishSubject<BaseUnit> subject = PublishSubject.create();
list = new ArrayList<>();
populateList(inputNumber).
subscribeOn(Schedulers.from(Executors.newFixedThreadPool(ThreadPool.getPoolSize())))
.subscribe(calculatedList -> {
list = calculatedList;
for (List<Integer> elem : list) {
for (ListOperationName operationName : ListOperationName.values()) {
ListUnit unit = new ListUnit(operationName, elem, 0);
calculate(unit);
unitList.add(unit);
subject.onNext(unit);
}
}
}, error -> Log.d("ERROR", error.toString()));
return subject;
}
public Observable<ArrayList<List<Integer>>> populateList(int inputNumber) {
return Observable.fromCallable(() -> {
ArrayList<List<Integer>> list = new ArrayList<>();
Integer[] populatedArray = new Integer[inputNumber];
Arrays.fill(populatedArray, insertValue);
list.add(new ArrayList<>(Arrays.asList(populatedArray)));
list.add(new LinkedList<>(Arrays.asList(populatedArray)));
list.add(new CopyOnWriteArrayList<>(Arrays.asList(populatedArray)));
return list;
});
}
然后尝试订阅主持人:
public void calculate(int inputNumber) {
fragment.showAllProgressBars();
repository.exec(inputNumber)
.observeOn(AndroidSchedulers.mainThread())
.subscribeOn(Schedulers.from(Executors.newFixedThreadPool(ThreadPool.getPoolSize())))
.subscribe(unit -> {
Log.d("PRESENTER RESULT", unit.toString());
fragment.setCellText(unit.getViewId(), unit.getTimeString());
}, error -> Log.d("PRESENTER ERROR", error.toString()));
}
这什么也没给我。但是,如果我使用ReplaySubject
-它会给我所有结果,但似乎只使用一个线程。因此,我认为订阅时出现了一些错误,应该早一些。
我需要使用PublishSubject
来给我提供结果,因为它们已经准备好使用多个线程。
该如何解决?也许还有其他问题?