Question

我正在尝试按销售集合中的产品进行分组，并将其总计相加，以了解哪些是我的应用程序中最畅销的产品。

MONGOOSE模型

import UIKit

class SecondViewController: UIViewController {

    @IBOutlet var textField: UITextField!
    @IBOutlet weak var bottomConstraint: NSLayoutConstraint!
    
    override func viewDidLoad() {
        super.viewDidLoad()
        view.backgroundColor = .darkGray
        NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillShow), name: UIResponder.keyboardWillShowNotification, object: nil)
        
        //The line below will display the keyboard over the UIView, thus obscuring it.
        textField.becomeFirstResponder()
    }

    @objc func keyboardWillShow(_ notification: Notification) {
        let info = notification.userInfo!
        let kbHeight = (info[UIResponder.keyboardFrameEndUserInfoKey] as! NSValue).cgRectValue.height
        
        bottomConstraint.constant = -kbHeight
        
        let duration: TimeInterval = (info[UIResponder.keyboardAnimationDurationUserInfoKey] as! NSNumber).doubleValue
        
        UIView.animate(withDuration: duration) { self.view.layoutIfNeeded() }
    }
}

const DHCustomerinvoiceSchema = mongoose.Schema（{

const mongoose = require('mongoose');

收藏示例

    Saledetail: {
        type: Array,
        required: true
    }, 
    date:{
       type: Date,
       required: true     
   },
   total:{
        type: Number,
        required: true  
   },
   pay:{
    type: Number,
    required: true,
    default: 0 
   },
   topay:{
     type: Number,
     required: true 
   },
   user:{
    type: mongoose.Schema.Types.ObjectId,
    required: true,
    ref: 'UserDH'
   },
   customer:{
       type: mongoose.Schema.Types.ObjectId,
       required: true,
       ref: 'DHcontacto'
   },
   state:{
       type: String,
       default: "OWED"  
   },
   created:{
    type: Date,
    default: Date.now()
   },


});

module.exports = mongoose.model('DHCustomerinvoice', DHCustomerinvoiceSchema);

分辨率：

{
    "id": "5ef6*****",
    "Saledetail": [
      {
        "id": "5ebf*****",
        "quantity": 9,
        "price": 2000,
        "totalline": 18000
      }
    ],
    "datesale": "1593129600000",
    "grandtotal": 18000,
    "user": "5eb9ab******",
    "customer": {
      "name": "isabella"
    },
    "state": "PAID"
  },

我使用了很多方法，这些方法实际上并没有给我带来这个结果，但是在找到我的最佳客户时，我取得了积极的结果，这些客户实际上是通过汇总，匹配和分组来开发它的，并且也应用了排序和限制... 但是在这个示例中，我并没有取得成功，我想这是因为采购细节的安排使馆藏的体系结构与众不同

Answer 1

我的信誉不足，无法评论您的问题。因此，我将其作为答案。

我认为您可以使用$ elemMatch在数组中搜索该项目。

const Productos = await Factura.aggregate([{ detlle: { $elemMatch: { $gte: 80, $lt: 85 } } }])

有关更多详细信息，elemMatch

Answer 2

在我的问题的答案下面

mostSellingProducts: async (_,{},ctx)=>{   
    
                const Products = await Invoice.aggregate([
                     { $unwind: "$Saledetail" },
                     { $match: { "state" : 'PAY'}},
                     { $group: {   
                        _id : { $toObjectId: "$Saledetail.id" },
                        total: { $sum: '$Saledetail.totalline' }
                    }},
                    {
                        $lookup: {
                            from: 'dhproducts',
                            localField: '_id',
                            foreignField: "_id",
                            as: "products" 
                        }
                    },
                    {
                        $limit: 4
                    },
                    {
                        $sort : {total: -1}
                    }
                    ]);
                return Products;
   },

如何使用猫鼬聚合来搜索集合中的数组

2 个答案: