$error1='';
$error2='';
$error3='';
$error4='';
$error5='';
$error6='';
$yourname='';
$email='';
$email2='';
$password='';
$password2='';
$country='';
if (isset($_POST['Registerme']))
{
$_POST['yourname']=$yourname;
$_POST['email']=$email;
$_POST['email2']=$email2;
$_POST['password']=$password;
$_POST['password2']=$password2;
$_POST['country']=$country;
if($yourname==''){
$error1='name required';
}
if($email==''){
$error2='email required';
}
if($email2==''){
$error3='required field';
}
if($password==''){
$error4='password required';
}
if($password2==''){
$error5='required field';
}
if($country==''){
$error6='country required';
}
if(empty($error1) && empty($error2) && empty($error3) && empty($error4) && empty($error5) && empty($error6))
{echo 'mysql query goes here and add the user to database';}
}///main one
else {$error1='';
$error2='';
$error3='';
$error4='';
$error5='';
$error6='';}
这是一个注册验证脚本。在我的注册表单中有两个电子邮件和密码filelds.second字段用于确认。我想检查天气用户在两个字段中键入相同的信息。如果我想在这个脚本中这样做我应该使用另一个if语句吗?或者我应该使用其他?我对这一步感到困惑......
答案 0 :(得分:1)
为第二个if语句添加其他条件。 例如
if($email=='' || $email != $email2){
...
答案 1 :(得分:1)
只需添加简单的支票即可。我不会将检查与一般密码检查结合起来 - 我可以想象你想告诉用户出了什么问题完全。
if ($password1 !== $password2) {
// Add an specific error saying the passwords do not match.
}
我会将松散错误的用户替换为如下数组:
$aErrors = array();
if ($password1 !== $password2) {
$aErrors[] = 'Another specific error!';
}
if (empty($password1) || empty($password2)) {
$aErrors[] = 'Another specific error';
}
if (empty($aErrors)) {
// Process the form!
}
答案 2 :(得分:1)
您的代码存在很多问题。
1. You are assinging $_POST['key'] = $somevalue, while I think you mean $somevar = $_POST['key']
2. Use an array for all error messages as it'll make your life a bit easier ..
3. To compare password use something like
if ($password1 !== $password2) {
}
所以......
$errors = array();
所以你要检查一下......
if ($password1 !== $password2) {
$errors[] = 'Password dont match';
}
if(count($errors) > 0) { //if there are errors
foreach($errors as $err) {
echo $err.' <br />';
}
} else {
// whatever you want to do if no error
}
我还建议您在查询中使用它们之前清理$ _POST值。 我希望它有所帮助。
答案 3 :(得分:1)
我认为你的意思是这样做:
$yourname = $_POST['yourname'];
$email = $_POST['email'];
$email2 = $_POST['email2'];
$password = $_POST['password'];
$password2 = $_POST['password2'];
$country = $_POST['country'];
其次使用了错误数组:
$errors = array();
第三次使用嵌套ifs(只是一个建议)
if (!empty($_POST['password1'])) {
if ($_POST['password1'] != $_POST['password2']) {
$errors[] = '<font color="red">The 2 passwords you have entered do not match.</font>';
} else {
$password = $_POST['password1'];
}
} else {
$errors[] = '<font color="red">Please provide a password.</font>';
}
答案 4 :(得分:1)
一些意见:
一些示例代码......:
// Simple sanitize function, complete it
function sanitize_input ($inputstr) {
return trim(mysql_real_escape_string($inputstr));
}
if (isset ($_POST['Registerme']) {
// array of error messages to report
$error_messages = array();
$isvalid = true;
// Assignment
$yourname = sanitize_input ($_POST['yourname']);
$email = sanitize_input ($_POST['email']);
$email2 = sanitize_input ($_POST['email2']);
$password = sanitize_input ($_POST['password']);
$password2 = sanitize_input ($_POST['password2']);
$country = sanitize_input ($_POST['country']);
// Validation
if (empty ($yourname)) {
$error_messages[] = "You must provide an username";
}
if (empty ($password)) {
$error_messages[] = "You must provide a password.";
}
elseif ($password !== $password2) {
$error_messages[] = "Passwords do not match.";
}
// Same for email, you caught the idea
// Finally, execute mysql code if all ok
if (empty($error_messages)) {
// Execute mysql code
isvalid = true;
}
}
// After form processing, use isvalid which is false if there are errors
// and the error_messages array to report errors