Question

我是Stack Overflow和C ++的新手，所以如果我问这个问题的格式不正确，请原谅。我正在努力回答以下问题，我也在下面发布了我的代码，请问我需要一些指导吗？

使用两个并行数组来跟踪其每个订阅的数量 50种出版物。数组“出版物”包含已发行杂志和报纸的名称和“订阅”数组包含每个相应杂志或报纸。您必须编写一个称为findMostSubs的void函数来确定哪个发布拥有最多的订阅者。函数findMostSubs必须返回发布的名称以及该发布的订阅者数量。假定以下全局常量：NUM_PUBS = 50;

#include <iostream>

using namespace std;

const int NUM_PUBS = 5;

void findMostSubs(string pubsP[NUM_PUBS], int subsP[NUM_PUBS], string mostSubsP, int nrMostSubsP)
{
   for (int i; i < NUM_PUBS; i++)
   {
      cout << "Please enter the name of the publication: ";
      cin >> pubsP[i];
      cout << "Please enter the number of subscriptions: ";
      cin >> subsP[i];
   }
   
   for (int i; i < NUM_PUBS; i++)
   {
      nrMostSubsP = 0;
      if (subsP[i] > nrMostSubsP)
      {
         nrMostSubsP = subsP[i];
         cout << nrMostSubsP;
      }
   }
}

int main()
{

   string publications[NUM_PUBS];
   int subscriptions[NUM_PUBS];
   int nrMostSubscriptions;
   string mostSubscriptions;

   findMostSubs(publications, subscriptions, mostSubscriptions, nrMostSubscriptions);

   return 0;
}

Answer 1

应该将findMostSub的最后两个参数声明为引用，以将它们用作输出：

void findMostSubs(string pubsP[NUM_PUBS], int subsP[NUM_PUBS], string& mostSubsP, int& nrMostSubsP)
{
   for (int i; i < NUM_PUBS; i++)
   {
      cout << "Please enter the name of the publication: ";
      cin >> pubsP[i];
      cout << "Please enter the number of subscriptions: ";
      cin >> subsP[i];
   }

   nrMostSubsP = subsP[0];   
   mostSubsP = pubsP[0];

   for (int i = 1; i < NUM_PUBS; i++)
   {
      if (subsP[i] > nrMostSubsP)
      {
         nrMostSubsP = subsP[i];
         mostSubsP = pubsP[i];
      }
   }
}

int main()
{

   string publications[NUM_PUBS];
   int subscriptions[NUM_PUBS];
   int nrMostSubscriptions;
   string mostSubscriptions;

   findMostSubs(publications, subscriptions, mostSubscriptions, nrMostSubscriptions);

   cout << "Most Subscriptions : " << mostSubscriptions << " , " << nrMostSubscriptions << endl;
   return 0;
}

遍历并行数组以确定C ++中的最大数量

1 个答案: