Question

我必须根据用户选择在两个表之间切换我可以使用表对象模型来做它但是它有问题，因为我删除一个表并加载另一个它将工作但下次当我切换回第一次它不会得到表格ID而不能正常工作。

使用DOM时这样

var tbl1  = document.createElement("table");

tbl1.setAttribute('id','shorttable');

for delete我在下面使用java脚本

var b = document.getElementById('shorttable');

document.removeChild(b);

但是给我异常

未捕获错误：NOT_FOUND_ERR：DOM异常

有没有办法用DOM做到这一点？

@lonesomeday感谢您的回复，但是当我从其他功能调用它时它无法正常工作？我想要的是这样的。

  <html>
  <head>
  <title>test dom</title>
  <script>

  function trackmode() 
{
    // i have to delete other table from this function where it is not working  
    var b = document.getElementById('shorttable');
    alert(b);
    b.parentNode.removeChild(b);

    var body = document.getElementsByTagName("body")[0];


    // creates a <table> element and a <tbody> element
    var tbl     = document.createElement("table");
    tbl.setAttribute('id','tracktable');
    var tblBody = document.createElement("tbody");

    // creating all cells
    for (var j = 0; j < 2; j++) {
        // creates a table row
        var row = document.createElement("tr");

        for (var i = 0; i < 2; i++) {
            // Create a <td> element and a text node, make the text
            // node the contents of the <td>, and put the <td> at
            // the end of the table row
            var cell = document.createElement("td");
            var cellText = document.createTextNode("cell is row "+j+", column "+i);
            cell.appendChild(cellText);
            row.appendChild(cell);
        }

        // add the row to the end of the table body
        tblBody.appendChild(row);
    }

    // put the <tbody> in the <table>
    tbl.appendChild(tblBody);
    // appends <table> into <body>
    body.appendChild(tbl);
    // sets the border attribute of tbl to 2;
    tbl.setAttribute("border", "2");
}


function shortenmode() 
{

     var b = document.getElementById('tracktable');
b.parentNode.removeChild(b);

    var body1 = document.getElementsByTagName("body")[0];
    // creates a <table> element and a <tbody> element
    var tbl1  = document.createElement("table");
    tbl1.setAttribute('id','shorttable');
    var tblBody1 = document.createElement("tbody");

    // creating all cells
    for (var j = 0; j < 2; j++) {
        // creates a table row
        var row = document.createElement("tr");

        for (var i = 0; i < 2; i++) {
            // Create a <td> element and a text node, make the text
            // node the contents of the <td>, and put the <td> at
            // the end of the table row
            var cell = document.createElement("td");
            var cellText = document.createTextNode("cell is row "+j+", column "+i);
            cell.appendChild(cellText);
            row.appendChild(cell);
        }

        // add the row to the end of the table body
        tblBody1.appendChild(row);
    }

    // put the <tbody> in the <table>
    tbl1.appendChild(tblBody1);
    // appends <table> into <body>
    body1.appendChild(tbl1);
    // sets the border attribute of tbl to 2;
    tbl1.setAttribute("border", "2");

         //here it will work
    //var b = document.getElementById('shorttable');
    //alert(b);
    //b.parentNode.removeChild(b);

    //myP.removeChild(myTextNode);
}


  </script>
  </head>
  <body >
 <button type="button" name="website" onclick=trackmode() > track</button>
 <button type="button" name="website1" onclick=shortenmode() > short </button>
 </body>
</html>

Answer 1

要删除元素，您需要将其从父中删除，而不是从文档中删除。所以：

b.parentNode.removeChild(b);

我们可以删除dom表吗？

1 个答案: