我已经可以使用表格下方的代码从该表格中获取多个详细信息...
我知道表看起来很奇怪,但这是客户端可用的数据表。
instance
下面是我用来获取详细信息的代码:
$ curl http://1.2.3.4:9100/metrics | grep instance
% Total % Received % Xferd Average Speed Time Time Time Current
Dload Upload Total Spent Left Speed
100 80082 0 80082 0 0 4383k 0 --:--:-- --:--:-- --:--:-- 4600k
$ curl http://1.2.3.4:9100/metrics | grep rkv1701
% Total % Received % Xferd Average Speed Time Time Time Current
Dload Upload Total Spent Left Speed
100 80085 0 80085 0 node_uname_info{domainname="(none)",machine="x86_64",nodename="rkv1701.myco.com",release="4.17.13-1.el7.elrepo.x86_64",sysname="Linux",version="#1 SMP Mon Aug 6 14:16:00 EDT 2018"} 1
0 9268k 0 --:--:-- --:--:-- --:--:-- 9776k
$
现在我要做的是获取下面的日期范围,以帮助仅显示来自 id | class | gender | e1 | e2 | d1 | d2
----------------------------------------------------------------------------------------------------------------------------------------------------------------
1 | class1 | male | ,first, first, first | ,first, first, first | , 2019-12-24,2019-12-24,2019-12-24 | ,2019-12-04,2019-11-21,2019-11-20 |
2 | class2 | female | ,second, second, second | ,second, second, second | ,2019-12-04,2019-11-21,2019-11-20 | , 2019-12-20,2019-12-20,2019-12-20
3 | class3 | male | ,first, first, first | ,third, third, third | ,2019-12-06,2019-12-13,2019-12-19 | ,2019-12-06,2019-12-13,2019-12-19
4 | class4 | male | ,third, third, third | ,third, third, third | ,2019-12-20,2019-12-20,2019-12-20 | ,2019-12-24,2019-12-24,2019-12-24
5 | class5 | female | ,second, second | ,third, third, third | ,2019-12-24,2019-12-24,2019-12-24 | ,2019-12-24,2019-12-24,2019-12-24
和$datfrm ="00/00/0001";
$datto ="31/12/2099";
$gender="male";
$place_map = ['first' => 1, 'second' => 0.8, 'third' => 0.4];
//e1view
$query = "SELECT e1 FROM eyfstb WHERE gender = '$gender'";
// perform the query ...
if ($result = $db->query($query)) {
$finalScore1 = 0;
$scores="";
$last_score="";
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
$efind = $row['e1'];
if (substr_count($efind, ",") >'2'){
$scores = explode(',', $row['e1']);
$last_score = trim($scores[count($scores)-1]);
$finalScore1 += $place_map[$last_score];
}
}
}
//e2view
$query = "SELECT e2 FROM eyfstb WHERE gender = '$gender'";
// perform the query ...
if ($result = $db->query($query)) {
$finalScore2 = 0;
$scores="";
$last_score="";
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
$efind = $row['e2'];
if (substr_count($efind, ",") >'2'){
$scores = explode(',', $row['e2']);
$last_score = trim($scores[count($scores)-1]);
$finalScore2 += $place_map[$last_score];
}
}
}
的记录
实际上我在下面尝试过此方法,但出现错误:
$datfrm
但是现在有了下面我尝试过的代码,我遇到了更多错误:
$datto
以下是显示的错误以及一个答案,我不确定它是否正确:
//Filter out dates between start and end date
$d1result = array_filter($d1view, function($data_item) use($datfrm,$datto) {
return $data_item >= $datfrm && $data_item <= $datto;
});
$e1result = array_intersect_key($e1view, $d1result);
我想要的结果是只获取e1和e2中位于d1和d2日期范围内的值 如果e1或e2字段中有2个文件,则我不希望它显示或映射任何内容。
答案 0 :(得分:1)
您想跳过e1
字段中没有3个元素的行。行后:
$efind = explode(',', $efind);
,添加此:
if (count($efind) !== 3) {
continue;
}
在两个地方都添加它。
代码中的另一个问题是,当您尝试比较日期时,您将字符串与<=
和>=
进行比较。您应该改用strcmp()。
在不了解表的全部内容的情况下,很难看到未定义索引错误的来源。
答案 1 :(得分:1)
首先,将日期更改为
$datfrm ="00/00/0001";
$datto ="31/12/2099";
到
$datfrm ="00-00-0001";
$datto ="31-12-2099";
然后添加
if (empty($last_score)) {
$last_score=0;
}else{
}
之间
$last_score = trim($scores[count($scores)-1]);
和
$finalScore15 += $place_map[$last_score];
应该可以完全解决您的问题。
答案 2 :(得分:0)
我希望这会有所帮助
<?php
$Date1 = '01-10-2010';
$Date2 = '07-12-2010';
$array = array();
$range = 0;
$Variable1 = strtotime($Date1);
$Variable2 = strtotime($Date2);
for ($currentDate = $Variable1; $currentDate <= $Variable2;
$currentDate += (86400)) {
$Store = date('Y-m-d', $currentDate);
$array[] = $Store;
$range++;
}
for ($i=0; $i < $range; $i++) {
echo $array[$i];
}
?>
答案 3 :(得分:0)
我在准确地了解您想要从e1和e2中获取什么时遇到了一些麻烦-假设它只是该字段中的最后一个值。如果我弄错了,可以在$ eview函数中更正它。
这里的代码使用您发布的数据得出的结果为4.2。
$datfrm = ""; // or something like '2010-01-01'
$datto = '2200'; // or something like '2015-12-01'
$gender="male";
$place_map = ['first' => 1, 'second' => 0.8, 'third' => 0.4];
// My understanding of the code is to get the weighted value of the
// last word in the column - if that's wrong, you can change this
// I am assuming you want the date that corresponded to the item you used
// for the final score, so if wrong, you need to change this.
// Also assume there will be the same number of dates as 'e's
//
// return false if bad value, or 0 if not in date range
$eview = function ($row, $ecol, $dcol) use ($place_map, $datfrm, $datto) {
$parts = array_filter(array_map('trim', explode(",", $row[$ecol])));
$dates = array_filter(array_map('trim', explode(",", $row[$dcol])));
if (!$parts || count($parts) != count($dates)) {
echo "Expected same number of parts and dates!\n";
return false;
}
$date = array_pop($dates); // Getting last date...
return ($date >= $datfrm && $date < $datto) ?
($place_map[array_pop($parts)] ?? false) : 0;
};
$finalScore1 = $finalScore2 = 0;
// perform the query ...
$query = "SELECT e1, e2, d1, d2 FROM eyfstb WHERE gender = '{$gender}'";
if ($result = $db->query($query)) {
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
$finalScore1 += $eview($row, 'e1', 'd1') ?: 0;
$finalScore2 += $eview($row, 'e2', 'd2') ?: 0;
}
}
echo ($finalScore1+$finalScore2) . "\n";
答案 4 :(得分:0)
你在做
if ($result = $db->query($query)) {
$finalScore1 = 0;
......
}
if ($result = $db->query($query)) {
$finalScore2 = 0;
.......
}
echo ($finalscore +$finalscore2);
尝试做:
$finalScore1 = 0;
if ($result = $db->query($query)) {
......
}
$finalScore2 = 0;
if ($result = $db->query($query)) {
.......
}
echo ($finalscore +$finalscore2);
您还没有定义,请首先定义:
$place_map = ['first' => 1, 'second' => 0.8, 'third' => 0.4];
希望这些可以解决您的错误,并根据数据和代码恢复结果