Question

我开始使用discord.py在discord上制作一个机器人，但有一个我无法解决的问题。目的是创建一个使bot消息成为具有特定消息的特定通道的命令。这是代码

@commands.has_any_role("Phantom","XX")
async def msg(ctx,*, Msg = None):
   await ctx.send(f"Please give the channel ID. You can do this by saying ``.ID (IDhere)``")
   @client.command()
   async def ID(ctx,*, ID = 0):
       message = Msg
       channel = client.get_channel(ID)
       await channel.send(message)
       await ctx.send(f":white_check_mark: Message sent")

我第一次运行整个命令时，一旦我说了.msg命令，我就收到了此错误：

  File "C:\Users\Jack\AppData\Local\Programs\Python\Python38-32\lib\site-packages\discord\ext\commands\bot.py", line 892, in invoke
    await ctx.command.invoke(ctx)
  File "C:\Users\Jack\AppData\Local\Programs\Python\Python38-32\lib\site-packages\discord\ext\commands\core.py", line 797, in invoke
    await injected(*ctx.args, **ctx.kwargs)
  File "C:\Users\Jack\AppData\Local\Programs\Python\Python38-32\lib\site-packages\discord\ext\commands\core.py", line 92, in wrapped
    raise CommandInvokeError(exc) from exc
discord.ext.commands.errors.CommandInvokeError: Command raised an exception: ClientException: Command ID is already registered.

Answer 1

使用该命令之前，您必须先注册该命令，因此解决方案是在程序顶部定义该命令，以便在启动时仅加载您要使用的所有命令。

您正在寻找的是：How to fix "discord.errors.ClientException: Command kick is already registered." error?

Discord.py Bot消息传递通道问题

1 个答案: