我收到未捕获的TypeError:当我导航到外部页面并尝试返回时,无法读取未定义的属性“用户名”。在渲染时,它会击中else语句,其中我返回false。有没有办法避免引发此错误?
render() {
const videos = this.randomHomeList();
const users = this.props.users;
const videoList = videos.map(video => {
if (video) {
const owner = users.filter(user => user.id === video.owner_id)
if (owner) {
const videoOwner = owner.find(user => user.username)
return (
<ul key={video.id} >
<div className="home-list-item">
<div className="home-video-header">
<h2 className="home-video-header-1">Added to</h2>
<h2 className="home-video-header-2">Foxeo Staff Picks</h2>
</div>
<Link to={`/play/${video.id}`}>
<video
className="home-video"
src={video.video_url}
poster=""
width="320"
height="240"
>
</video>
</Link>
<h2 className="video-title">{video.video_title}</h2>
<h2 className="video-upload-date">uploaded {this.dateCreated(video.created_at)}</h2>
<h2 className="video-owner-name">{videoOwner.username}</h2>
</div>
</ul>
)
} else {
return false;
}
}
})
答案 0 :(得分:3)
您可以在此处进行检查,并执行以下操作:
<h2 className="video-owner-name">{videoOwner ? videoOwner.username : ""}</h2>
答案 1 :(得分:2)
您可以使用类型安全运算符。
?是安全导航操作员。它检查变量是null还是在模板中未定义。如果为null且未定义,则该值不会引发错误。
<h2 className="video-owner-name">{videoOwner?.username}</h2>
第二个选择是使用上一个答案中建议的三元运算符。
<h2 className="video-owner-name">{videoOwner ? videoOwner.username : ""}</h2>