我修改了beej的网络示例指南(如下所示),将html响应传回浏览器。我每次刷新都会“重置连接”,似乎无法找出原因?就像它在发出html响应之前关闭连接一样。
任何想法或调试建议?
编辑:它有时会将正确的数据传递给浏览器。
以下是代码:
/*
** server.c -- a stream socket server demo
*/
#include <iostream>
#include <string>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <errno.h>
#include <string.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netdb.h>
#include <arpa/inet.h>
#include <sys/wait.h>
#include <signal.h>
#define PORT "8080" // the port users will be connecting to
#define BACKLOG 10000 // how many pending connections queue will hold
using namespace std;
void sigchld_handler(int s)
{
while(waitpid(-1, NULL, WNOHANG) > 0);
}
// get sockaddr, IPv4 or IPv6:
void *get_in_addr(struct sockaddr *sa)
{
if (sa->sa_family == AF_INET) {
return &(((struct sockaddr_in*)sa)->sin_addr);
}
return &(((struct sockaddr_in6*)sa)->sin6_addr);
}
int main(void)
{
int sockfd, new_fd; // listen on sock_fd, new connection on new_fd
struct addrinfo hints, *servinfo, *p;
struct sockaddr_storage their_addr; // connector's address information
socklen_t sin_size;
struct sigaction sa;
int yes=1;
char s[INET6_ADDRSTRLEN];
int rv;
memset(&hints, 0, sizeof hints);
hints.ai_family = AF_UNSPEC;
hints.ai_socktype = SOCK_STREAM;
hints.ai_flags = AI_PASSIVE; // use my IP
if ((rv = getaddrinfo(NULL, PORT, &hints, &servinfo)) != 0) {
fprintf(stderr, "getaddrinfo: %s\n", gai_strerror(rv));
return 1;
}
// loop through all the results and bind to the first we can
for(p = servinfo; p != NULL; p = p->ai_next) {
if ((sockfd = socket(p->ai_family, p->ai_socktype,
p->ai_protocol)) == -1) {
perror("server: socket");
continue;
}
if (setsockopt(sockfd, SOL_SOCKET, SO_REUSEADDR, &yes,
sizeof(int)) == -1) {
perror("setsockopt");
exit(1);
}
if (bind(sockfd, p->ai_addr, p->ai_addrlen) == -1) {
close(sockfd);
perror("server: bind");
continue;
}
break;
}
if (p == NULL) {
fprintf(stderr, "server: failed to bind\n");
return 2;
}
freeaddrinfo(servinfo); // all done with this structure
if (listen(sockfd, BACKLOG) == -1) {
perror("listen");
exit(1);
}
sa.sa_handler = sigchld_handler; // reap all dead processes
sigemptyset(&sa.sa_mask);
sa.sa_flags = SA_RESTART;
if (sigaction(SIGCHLD, &sa, NULL) == -1) {
perror("sigaction");
exit(1);
}
printf("server: waiting for connections...\n");
while(1) { // main accept() loop
sin_size = sizeof their_addr;
new_fd = accept(sockfd, (struct sockaddr *)&their_addr, &sin_size);
if (new_fd == -1) {
cout << "accept fail" << endl;
continue;
}
inet_ntop(their_addr.ss_family,
get_in_addr((struct sockaddr *)&their_addr),
s, sizeof s);
printf("server: got connection from %s\n", s);
if (!fork()) { // this is the child process
close(sockfd); // child doesn't need the listener
string response = "HTTP/1.0 200 OK\r\n\r\n<html><head><title>Test</title></head><body>ok!</body></html>";
if (send(new_fd, response.c_str(), response.length(), 0) == -1)
cout << "error" << endl;
close(new_fd);
cout << "sent." << endl;
exit(0);
}
close(new_fd); // parent doesn't need this
}
return 0;
}
答案 0 :(得分:3)
所以这里有2个错误(实际上有3个错误,最后一个是如果你想与浏览器交谈,你必须正确地实现HTTP,这是非常重要的)
您在接受客户时立即发送回复。有点慢的浏览器可能会在它发送完请求之前收到响应 - 这会使浏览器感到困惑。
您没有阅读请求。这意味着当你关闭套接字时,会有未读数据,这将导致在关闭套接字时发送TCP RST(导致“连接重置......”错误)。在某些情况下,浏览器会在此之前读取响应,在其他情况下可能没有,(在某些情况下,我猜它会因为没有Content-Length:标题而混淆,所以浏览器不会不知道它是否应该在遇到TCP RST时接收更多数据。这种特殊情况更好地描述了here