弹簧反应，按顺序处理任务

Question

这是我想要获取结果并始终将monoUserContent设为空的所需代码

public Mono<UserResponse> functionABC(){
   Mono<List<User>> monoUserType = service.getType(); //calling service
   Mono<List<Content>> monoUserContent = service.getUserContent(userType);

   Mono<UserResponse> response = null;

   Mono<Tuple2<List<User>, List<Content>> zipped = Mono.zip(monoUserType, monoUserContent);
   response = zipped.flatMap( t -> {
     List<User> tupleUserType = tuple.getT1();
     List<Content> tupleUserContent = tuple.getT2();
     Mono<UserResponse> userRes = userCombinator.bindData(tupleUserType, tupleUserContent );
     return userRes;
   });
   return response;
}

在运行以下代码段时，

public Mono<UserResponse> functionABC(){
   Mono<List<User>> monoUserType = service.getType(); //calling service
   Mono<List<Content>> monoUserContent = service.getUserContent(userType);
    
   try {
      thread.sleep(3000);
   } catch(Exception e) {
      e.printStackTrace();
   }
   Mono<UserResponse> response = null;
    
   Mono<Tuple2<List<User>, List<Content>> zipped = Mono.zip(monoUserType, monoUserContent);
   response = zipped.flatMap( t -> {
      List<User> tupleUserType = tuple.getT1();
      List<Content> tupleUserContent = tuple.getT2();
      Mono<UserResponse> userRes = userCombinator.bindData(tupleUserType, tupleUserContent );
      return userRes;
    });
    
   return response ;
}

它为我工作。添加thread.sleep（5000），神奇了。

我知道这不是正确的方法，我该如何处理这种情况？