Question

我想整理一列，但是基于不同的交易类型，并且这些总和只出现在一行中。

我的SQL（SQL Server 2000）如下所示：

SELECT c.customername,
       CASE WHEN t.transactiontypekey IN (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19) THEN SUM(t.tranamount) ELSE 0 END as 'Tot-Exp',
       CASE WHEN t.transactiontypekey IN (20,21,22,23,30,32,34,36) THEN SUM(t.tranamount) ELSE 0 END as 'Tot-Rev',
       CASE WHEN t.transactiontypekey IN (31,33,35,37) THEN SUM(t.tranamount) ELSE 0 END as 'Tot-Fee'
FROM customers c, transactions t
WHERE c.customerkey = t.customerkey
GROUP BY c.customername, t.transactiontypekey
ORDER BY c.customername

在上面的SQL中，交易类型分为费用，收入和费用，上面的输出显示为：

customernameTot-Exp  Tot-Rev    Tot-Fee
CUSTOMER1   13.3900    .0000      .0000
CUSTOMER1     .0000 549.0000      .0000
CUSTOMER1     .0000    .0000    60.0000
CUSTOMER1     .0000    .0000      .0000

如何让我的输出看起来像：

customername     Tot-Exp   Tot-Rev  Tot-Fee
CUSTOMER1         13.390    549.00   60.000

每个客户只有一行，只有那一行中't.tranamount'列的所有总数？

Answer 1

总结CASE表达式本身;

SUM(CASE WHEN t.transactiontypekey IN (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19) THEN t.tranamount ELSE 0 END) as 'Tot-Exp',

从t.transactiontypekey删除GROUP BY。

只有一行的一列总和？

1 个答案: