火花udf没有被调用

Question

给出以下示例：

import org.apache.spark.sql.expressions.UserDefinedFunction
import org.apache.spark.sql.functions._

val testUdf: UserDefinedFunction = udf((a: String, b: String, c: Int) => { 
  val out = s"test1: $a $b $c"
  println(out)
  out
})

val testUdf2: UserDefinedFunction = udf((a: String, b: String, c: String) => { 
  val out = s"test2: $a $b $c"
  println(out)
  out
})

Seq(("hello", "world", null))
.toDF("a", "b", "c")
.withColumn("c", $"c" cast "Int")
.withColumn("test1", testUdf($"a", $"b", $"c"))
.withColumn("test2", testUdf2($"a", $"b", $"c"))
.show

testUdf似乎没有被调用。没有错误，没有警告，它只返回null。

有没有办法检测这些无声故障？还有，这是怎么回事？

火花2.4.4 Scala 2.11

Answer 1

标量类型“ Int”不允许为空。变量“ c”类型可以更改为“整数”。

Answer 2

我不知道是什么原因造成的。但是我认为这很可能是由于隐式转换

代码1

    val spark = SparkSession.builder()
      .master("local")
      .appName("test")
      .getOrCreate()
    import spark.implicits._
    val testUdf: UserDefinedFunction = udf((a: String, b: String, c: Int) => {
      val out = s"test1: $a $b $c"
      println(out)
      out
    })
    
    Seq(("hello", "world", null))
      .toDF("a", "b", "c")
      .withColumn("test1", testUdf($"a", $"b", $"c"))
      .show

代码2

    val spark = SparkSession.builder()
      .master("local")
      .appName("test")
      .getOrCreate()
    import spark.implicits._
    val testUdf: UserDefinedFunction = udf((a: String, b: String, c: String) => {
      val out = s"test1: $a $b $c"
      println(out)
      out
    })

    Seq(("hello", "world", null))
      .toDF("a", "b", "c")
      .withColumn("test1", testUdf($"a", $"b", $"c"))
      .show

代码1逻辑计划

代码2逻辑计划

Answer 3

当您尝试将其强制转换为null时，您应该会遇到一个scala.MatchError: scala.Null错误，此外您对UDF的定义对我不起作用，因为我在尝试注册时得到了一个java.lang.UnsupportedOperationException: Schema for type AnyRef is not supported。

那呢：

import org.apache.spark.sql.expressions.UserDefinedFunction
import org.apache.spark.sql.functions._

def testUdf(a: String, b: String, c: Integer): String = { 
  val out = s"test1: $a $b $c"
  println(out)
  out
}

def testUdf2(a: String, b: String, c: String): String = { 
  val out = s"test2: $a $b $c"
  println(out)
  out
}

val yourTestUDF = udf(testUdf _)
val yourTestUDF2 = udf(testUdf2 _)

// spark.udf.register("yourTestUDF", yourTestUDF) // just in case you need it in SQL

spark.createDataFrame(Seq(("hello", "world", null.asInstanceOf[Integer])))
.toDF("a", "b", "c")
.withColumn("test1", yourTestUDF($"a", $"b", $"c"))
.withColumn("test2", yourTestUDF2($"a", $"b", $"c"))
.show(false)

输出：

test1: hello world null
test2: hello world null
+-----+-----+----+-----------------------+-----------------------+
|a    |b    |c   |test1                  |test2                  |
+-----+-----+----+-----------------------+-----------------------+
|hello|world|null|test1: hello world null|test2: hello world null|
+-----+-----+----+-----------------------+-----------------------+