我被困住了。我实现了将GridView FooterTemplate中的复选框和文本框控件中的新DB值插入到SQLDataSource中所需的所有步骤,但是当我单击“添加”按钮以激活“插入”命令时,我的页面会闪烁并且不会发生插入。就实际的SQL而言,我有一个存储过程设置为GridView的DataSource的插入操作。我已经单独测试了这个程序,它运行正常。
我的设计基于这篇文章:http://www.aspdotnetfaq.com/Faq/How-to-insert-row-in-GridView-with-SqlDataSource.aspx我的错误可能在我的事件处理程序中。知道我错过了什么吗?
发布所有GridView代码太长了,所以这里有一些基本要点:
插入按钮的FooterTemplate:
<asp:GridView ID="CartonGridView" runat="server" AutoGenerateColumns="False"
CellPadding="6" DataKeyNames="CartonID" Width="100%"
DataSourceID="Carton_Table" ForeColor="#333333"
GridLines="None" AllowSorting="True">
<RowStyle BackColor="#F7F6F3" ForeColor="#333333" />
<Columns>
<asp:TemplateField ShowHeader="False">
<EditItemTemplate>
<asp:Button ID="Button1" runat="server" CausesValidation="True"
CommandName="Update" Text="Update" />
<asp:Button ID="Button2" runat="server" CausesValidation="False"
CommandName="Cancel" Text="Cancel" />
</EditItemTemplate>
<ItemTemplate>
<asp:Button ID="Button1" runat="server" CausesValidation="False"
CommandName="Edit" Text="Edit" />
</ItemTemplate>
<FooterTemplate>
<asp:Button ID="Button1" runat="server" CausesValidation="True"
CommandName="Insert" Text="Add" />
<asp:Button ID="Button2" runat="server" CausesValidation="False"
CommandName="Cancel" Text="Cancel" />
</FooterTemplate>
</asp:TemplateField>
...
SQLDataSource绑定到Gridview:
<asp:SqlDataSource ID="Carton_Table" runat="server"
ConnectionString="<%$ ConnectionStrings:DBConnectionString %>"
InsertCommand="spCartonInsert" InsertCommandType="StoredProcedure"
SelectCommand="spCartonSelect" SelectCommandType="StoredProcedure"
UpdateCommand="spCartonUpdate" UpdateCommandType="StoredProcedure">
...
<InsertParameters>
<asp:Parameter Name="Active" Type="Boolean" />
<asp:Parameter Name="Value" Type="String" />
<asp:Parameter Name="Description" Type="String" />
</InsertParameters>
插入事件处理程序:
protected void CartonGridView_RowCommand(object sender, GridViewCommandEventArgs e)
{
if (e.CommandName == "Insert")
{
CheckBox Active = CartonGridView.FooterRow.FindControl("InsertActive") as CheckBox;
TextBox SAPCode = CartonGridView.FooterRow.FindControl("InsertSAPCode") as TextBox;
TextBox Description = CartonGridView.FooterRow.FindControl("InsertDescription") as TextBox;
SqlParameter paramActive = new SqlParameter("@Active", SqlDbType.Bit);
paramActive.Direction = ParameterDirection.Input;
paramActive.Value = Active.Checked;
insertParameters.Add(paramActive);
SqlParameter paramValue = new SqlParameter("@Value", SqlDbType.NVarChar, 30);
paramValue.Direction = ParameterDirection.Input;
paramValue.Value = paramValue.Text;
insertParameters.Add(paramValue);
SqlParameter paramDescription = new SqlParameter("@SAP_Long_Description", SqlDbType.NVarChar, 250);
paramDescription.Direction = ParameterDirection.Input;
paramDescription.Value = Description.Text;
insertParameters.Add(paramDescription);
Carton_Table.Insert();
}
}
protected void Carton_Table_Inserting(object sender, SqlDataSourceCommandEventArgs e)
{
e.Command.Parameters.Clear();
foreach (SqlParameter p in insertParameters)
e.Command.Parameters.Add(p);
}
答案 0 :(得分:0)
是的,事件处理程序没有连线。
<asp:GridView ID="CartonGridView" runat="server" AutoGenerateColumns="False"
CellPadding="6" DataKeyNames="CartonID" Width="100%"
DataSourceID="Carton_Table" ForeColor="#333333"
GridLines="None" AllowSorting="True"
onrowcommand="CartonGridView_RowCommand">