是否可以在DataGridView中有一个列作为ComboBox，允许用户输入新值？

Question

我知道在正常ComboBox中，如果FlatStyle为Standard，则用户将能够键入不在Items列表中的值。但是，如果DataGridView中的组合框为Standard，则不会让我输入新值。是否可以在DataGridView？

的列中实现此功能

Answer 1

好吧，在DataGridView中，您可以添加DataGridViewComboBoxColumn类型的列。它是DisplayStyle和/或FlatStyle取决于当前行状态。我想当你添加一个新行（编辑模式）时，你可以为它添加值。

参考文献： Add items to DataGridViewComboBoxColumn in DataGridView during runtime http://www.lazycoder.com/weblog/2006/09/12/adding-values-to-the-datagridviewcomboboxcell-at-runtime/

Answer 2

    private void dataGridView2_EditingControlShowing(object sender, DataGridViewEditingControlShowingEventArgs e)
    {
        try
        {
            switch (dataGrid_ItemsList.Columns[dataGrid_ItemsList.SelectedCells[0].ColumnIndex].HeaderText)
            {
                case "Batch":
                    if (e.Control is ComboBox)
                    {
                        ComboBox _with1 = (ComboBox)e.Control;
                        _with1.DropDownStyle = ComboBoxStyle.DropDown;
                        _with1.AutoCompleteMode = AutoCompleteMode.SuggestAppend;
                        _with1.AutoCompleteSource = AutoCompleteSource.CustomSource;
                        _with1.AutoCompleteCustomSource = BatchList;
                        //_with1.Validating -= HandleComboBoxValidating;
                        //_with1.Validating += HandleComboBoxValidating;

                        _with1.Validating += (ss, ee) =>
                        {
                            if (!_with1.Items.Contains(_with1.Text))
                            {
                                var comboColumn = dataGrid_ItemsList.CurrentCell as DataGridViewComboBoxCell;
                                _with1.Items.Add(_with1.Text);
                                _with1.Text = _with1.Text;
                                comboColumn.Items.Add(_with1.Text);
                                this.dataGrid_ItemsList.CurrentCell.Value = _with1.Text;
                            }
                        };
                    }
                    break;
            }
        }
        catch (Exception ex)
        {
            _CommonClasses._Cls_ExceptionsHandler.HandleException(ex,false);
        }
    }