用户通过PHP填写表单后如何自动生成页面?

时间:2011-06-07 06:04:54

标签: php html forms directory

假设我有一个包含两个输入字段,标题和注释的表单。在用户填写两个字段并提交数据后,将自动创建一个页面,其中包含用户键入的标题和注释,位于根目录中的文件夹中,例如www.root.com/page/将包含自动生成页面。

更新

我希望将表单数据发送到SQL表行,并将自动生成页面的url与标题和注释放在同一个SQL行中。

我如何通过PHP执行此操作?

1 个答案:

答案 0 :(得分:6)

<?php
//Template for basic page
$template = <<<EOD
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title><!--TITLE--></title>
</head>

<body>
<!--COMMENT-->
</body>
</html>
EOD;

//handle the posted form
if(isset($_POST['title'])&&isset($_POST['comment'])){
    //replace the areas of the template with the posted values
    $page = str_replace('<!--TITLE-->',htmlentities($_POST['title']),$template);
    $page = str_replace('<!--COMMENT-->',htmlentities($_POST['comment']),$page);
    //create a name for the new page
    $pagename = md5($_POST['title']).'.html';

    //db connect & select
    $db=mysql_connect('localhost','user','pass');
    mysql_select_db('yourdb');

    //check if page already exists
    $result = mysql_query('SELECT pagename from yourtable WHERE url="'.mysql_real_escape_string($pagename).'"');
    if(mysql_num_rows($result)>=1){
        $notice = '<p>Page already created <b>./pages/'.$pagename.'</b></p>';
    }else{
        //inset new page into db
        mysql_query('INSERT into yourtable (`id`,`title`,`comment`,`url`)VALUES("",
        "'.mysql_real_escape_string(htmlentities($_POST['title'])).'",
        "'.mysql_real_escape_string(htmlentities($_POST['comment'])).'",
        "'.$pagename.'")');
        //put the created content to file
        file_put_contents('./pages/'.$pagename,$page);
        //make a notice to show the user
        $notice = '<p>New Page created <b>./pages/'.$pagename.'</b></p>';
    }
}
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Language" content="en-gb">

<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Make page example</title>
</head>

<body>
<?php
//if the notice is set then display it
if(isset($notice)){echo $notice;} ?>
<form method="POST" action="">
  <p>Title:<input type="text" name="title" size="31"></p>
  <p>Comment:</p>
  <p><textarea rows="5" name="comment" cols="21"></textarea></p>
  <p><input type="submit" value="Submit"></p>
</form>
</body>
</html>