我目前在我的页面上有一些脚本可以解析我在线广播电台的标题/艺术家信息。我使用
在html中将其显示为纯文本<span id="song_title"></span>
如何获取进入span id的动态信息并将其用于“post to twitter”链接,以便听众可以在Twitter上分享当前的歌曲名称?
我做了一些研究,并发现了一些关于发布到Twitter的变化,但我发布这个动态文本没有运气。
这是脚本代码:
<!-- Begin Now Playing Script -->
<script>
(function () {
// we need a JSON parser, if it does not exist, load it
if (typeof JSON == "undefined") {
var s = document.createElement("script");
// json2.js retrieved from https://github.com/douglascrockford/JSON-js
s.src = "json2.js";
document.getElementsByTagName("head").appendChild(s);
}
})();
var song_ends = 0;
function update_song () {
if ((new Date).getTime() < song_ends) {
// use cached result as the song has not ended yet
return;
}
var req = new XMLHttpRequest();
// IE compatbility:
var textContent = 'textContent' in document ? 'textContent' : 'innerText';
req.onreadystatechange = function () {
if (req.readyState == 4) {
var song = JSON.parse(req.responseText);
if (song.title) {
var img = document.getElementById("song_image");
if(song.image.src){
img.alt = song.image.alt;
img.src = song.image.src;
img.width = 100;
img.height = 100;
}else{
img.src="images/default_art.png";
img.width = 100;
img.height = 100;
}
document.getElementById("song_title")[textContent] = song.title ;
document.getElementById("song_artist")[textContent] = song.artist;
document.getElementById("song_next")[textContent] = song.next ;
// store the end date in javascript date format
song_ends = (new Date).getTime() + song.wait_ms;
}
}
};
req.open('get', 'php/PlayingNow.php', true);
req.send(null);
}
// poll for changes every 20 seconds
setInterval(update_song, 20000);
// and update the song information
update_song();
</script>
<!-- End Now Playing Script -->
我希望能够像这样发布到Twitter:目前通过(song_artist)收听(song_title)
以下是上述脚本中引用的PHP文件的代码:
<?php // filename: PlayingNow.php
$json = null;
$cache = 'song.json';
// if there is no usuable cache
if (!$json) {
// retrieve the contents of the URL
$ch = curl_init('http://bigcountry.streamon.fm/card');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$res = curl_exec($ch);
curl_close($ch);
$json = json_decode($res);
// if the title exists, assume the result to be valid
if ($json && $json->title) {
// cache it
$fp = fopen('song.json', 'w');
fwrite($fp, $res);
fclose($fp);
} else {
$json = null;
}
}
if ($json) {
$info = array();
// contains the time in milliseconds
$info['wait_ms'] = $json->interval->ends_at - 1000 * microtime(true);
$info['title'] = $json->title ;
$info['artist'] = $json->artist;
$info['album'] = $json->album ;
$info['next'] = $json->next_song;
$info['image'] = $json->album_art;
// display a JSON response for the HTML page
echo json_encode($info);
}
?>
答案 0 :(得分:1)
执行此操作的“正确”方法是使用Twitter Web Intents,这是专为此方案设计的。请查看"Tweet or Reply to a Tweet"部分。实际上,您只需在页面上包含Web Intents脚本(http://platform.twitter.com/widgets.js
),创建链接并设置其href
,例如:
var link = document.createElement('a');
link.innerHTML = "Link Text";
link.href = 'http://twitter.com/intent/tweet?text=Currently listening to "' + songTitle + '" by ' + songArtist;
var parentElement = document.getElementById('SOME_ELEMENTS_ID');
parentElement.appendChild(link);
如果您还希望推文包含您网站的网址,则可以添加url
参数。