Question

这是用于像使用公平密码一样对邮件进行加密的代码。

def encrypt(input_message):
    r1=r2=c1=c2=0
    play = playfair()
    listed_ip = list(input_message)
    j=1
    listed_op=list('#####################################################################################################################################################')
    for i in range(len(listed_ip)-1):
        first_letter = listed_ip[i]
        second_letter = listed_ip[j]
        if first_letter =='j':
            listed_ip[i] = 'i'
        if second_letter == 'j':
            listed_ip[j] = 'i'
        for row in range(5):
            for col in range(5):
                if play[row][col] ==first_letter:
                    r1=row
                    c1=col
                if play[row][col] == second_letter:
                    r2=row
                    c2=col
            if r1 == r2:
                listed_op[i] = play[r1][(c1+1)%5]
                listed_op[j] = play[r2][(c2 + 1) % 5]
            elif c1 ==c2:
                listed_op[i] = play[(r1+1)%5][c1]
                listed_op[j] = play[(r2+1)%5][c2]
            else:
                listed_op[i]=play[r1][c2]
                listed_op[j]=play[r2][c1]
            i+=2
            j+=2
    output_text = ''.join(listed_op)
    print(output_text)
encrypt('Hithisisvishal')

我应该得到一个输出，该输出会更改此输入消息，其中根据每个字母在矩阵中的位置，将每个字母替换为另一个字母。

用来检查每个字母的位置的矩阵的另一个函数是：

import numpy as np


def playfair():
    key = input('Enter the key :')
    key += 'abcdefghiklmnopqrstuvwxyz '
    size = len(key)
    listed_key=list(key)

    for i in range(size):
        if listed_key[i] == 'j':
            listed_key[i] = 'i'
        for j in range(i+1, size):
            if listed_key[j] == listed_key[i]:
                for k in range(j, size-1):
                    listed_key[k] = listed_key[k+1]
                size -= 1
            else : j += 1
    final_key = ''.join(listed_key)
    play = np.zeros((5, 5), 'U1')

    play.flat[:32] = list(final_key)
    return play

我得到的错误是：

Enter the keysecc

---------------------------------------------------------------------------
IndexError                                Traceback (most recent call last)
<ipython-input-6-dd6ef9446893> in <module>
     33     output_text = ''.join(listed_op)
     34     print(output_text)
---> 35 encrypt('Hithisisvishal')

<ipython-input-6-dd6ef9446893> in encrypt(input_message)
      7     for i in range(len(listed_ip)-1):
      8         first_letter = listed_ip[i]
----> 9         second_letter = listed_ip[j]
     10         if first_letter =='j':
     11             listed_ip[i] = 'i'

IndexError: list index out of range

Answer 1

您的i和j没有正确分配。

for i in range(len(listed_ip)-1):

变量i将为0、1、2，... ...设置i + = 2后，将在循环返回时将其重置。变量j在第二个for循环内更新。因此，您有索引错误。

def encrypt(input_message):
    r1 = r2 = c1 = c2 = 0
    play = playfair()
    listed_ip = list(input_message)
    j = 1
    listed_op = list('#'*150)

    for i in range(0, len(listed_ip)-1, 2):
        j = i + 1
        first_letter = listed_ip[i]
        second_letter = listed_ip[j]
        if first_letter == 'j':
            listed_ip[i] = 'i'
        if second_letter == 'j':
            listed_ip[j] = 'i'
        for row in range(5):
            for col in range(5):
                if play[row][col] == first_letter:
                    r1 = row
                    c1 = col
                if play[row][col] == second_letter:
                    r2 = row
                    c2 = col
            if r1 == r2:
                listed_op[i] = play[r1][(c1+1) % 5]
                listed_op[j] = play[r2][(c2 + 1) % 5]
            elif c1 == c2:
                listed_op[i] = play[(r1+1) % 5][c1]
                listed_op[j] = play[(r2+1) % 5][c2]
            else:
                listed_op[i] = play[r1][c2]
                listed_op[j] = play[r2][c1]
            # i += 2
            # j += 2
    output_text = ''.join(listed_op)
    print(output_text)

Answer 2

您的问题似乎是您的j值对于数组而言太大了。当前，对于listing_ip中的每个元素，您的j值将增加十。以这种速率，它只需要两次迭代就可以超出list_ip的长度并抛出IndexError。对此的可能解决方法是在for循环内而不是之前将j值设置为1。这样，对于listed_ip中的每个值，您都从j = 1开始。

这里是我的解决方法：

def encrypt(input_message):
    r1=r2=c1=c2=0
    play = playfair()
    listed_ip = list(input_message)
    print(listed_ip)
    
    listed_op=list('#####################################################################################################################################################')
    for i in range(len(listed_ip)-1):
        j=1
        first_letter = listed_ip[i]
        second_letter = listed_ip[j]
        if first_letter =='j':
            listed_ip[i] = 'i'
        if second_letter == 'j':
            listed_ip[j] = 'i'
        for row in range(5):
            for col in range(5):
                if play[row][col] ==first_letter:
                    r1=row
                    c1=col
                if play[row][col] == second_letter:
                    r2=row
                    c2=col
            if r1 == r2:
                listed_op[i] = play[r1][(c1+1)%5]
                listed_op[j] = play[r2][(c2 + 1) % 5]
            elif c1 ==c2:
                listed_op[i] = play[(r1+1)%5][c1]
                listed_op[j] = play[(r2+1)%5][c2]
            else:
                listed_op[i]=play[r1][c2]
                listed_op[j]=play[r2][c1]
            i+=2
            j+=2
    output_text = ''.join(listed_op)
    print(output_text)
encrypt('Hithisisvishal')

这只是对那一行的更改，看看它是否对您有用

索引错误：索引超出范围，但是它不应该超出范围，我尝试跟踪它

2 个答案: