SQL获取一些组并保持顺序

时间:2020-06-23 16:28:02

标签: sql select google-bigquery window-functions gaps-and-islands

我有如下示例数据。

width

现在我希望结果应该是这样的:

+---------+------------+--------+
| user id |   sequence | Action |
|---------|------------|--------|
| 12345   |    1       | Run    |
| 12345   |    2       | Sit    |
| 12345   |    3       | Sit    |
| 12345   |    4       | Run    |
| 12345   |    5       | Run    |
| 12345   |    6       | Sit    |
+---------+------------+--------+

应将序列#2和#3的行合并,将#4和#5的行合并。 我使用“按操作分组”将获得如下表所示的答案,但这不是我想要的:

+---------+---------+
| user id |  Action |
|---------|---------|
| 12345   |  Run    |
| 12345   |  Sit    |
| 12345   |  Run    |
| 12345   |  Sit    |
+---------+---------+

如何实现SQL(我使用Google Bigquery)?

感谢一百万!

2 个答案:

答案 0 :(得分:1)

下面是BigQuery标准SQL

#standardSQL
SELECT * EXCEPT(dup) FROM (
  SELECT *, action = LAG(action, 1, '') OVER(PARTITION BY user_id ORDER BY sequence) AS dup
  FROM `project.dataset.table`
)
WHERE NOT dup

如果要应用于您的问题的样本数据-输出为

Row user_id sequence    action   
1   12345   1           Run  
2   12345   2           Sit  
3   12345   4           Run  
4   12345   6           Sit  

答案 1 :(得分:0)

您可以使用窗口函数:其想法是将每行的操作与“上一个”操作进行比较,并在值更改的行上进行过滤:

select *
from (
    select t.*, lag(action) over(partition by user_id order by sequence) lag_action
    from mytable t
) t
where action <> lag_action or lag_action is null