我知道这个问题看起来令人困惑,但说实话,它看起来并不像那样。 我正在建立一个关于无人机的程序(抱歉,如果没有意义的话) 从此代码中,我得到错误“(行116)标识符“ camrecord”未定义”和“编译器错误C2065 “(第116行)标识符”:未声明的标识符”,尽管我已经识别并声明了它们?如何解决呢? 谢谢
#include<iostream>
#include <fstream>
#include <cstdlib>
#include <iomanip>
#include <string.h>
using namespace std;
void manualMode();
void defaultMode();
void Getdata(double & camrecord, double & Projectframerate);
void calculate(double & camrecord, double & Projectframerate, double & actualframerate);
int speed, timeTofly, operation;
int angle = 90;
int main() {
int mode = 0, part = 3;
double flyLevel;
int obstacleSensor = 0, timer = 3, AccelerometerSensor = 0, tempSensor = 25;
char startPause;
cout << "Drone Flying Technology" << endl;
do {
cout << "Choose Mode: (1)Default, (2)Manual \n";
cin >> mode;
if (mode == 1)
defaultMode();
if (mode == 2)
manualMode();
} while (mode == 0);
cout << "Choose how to fly: (1)Upper , (2)Lower , (3)Upper and Lower \n";
cin >> part;
switch (part) {
case 1:
case 2:
flyLevel = 0.5;
break;
case 3:
flyLevel = 1;
break;
}
if (obstacleSensor == 0) {
do {
cout << "Press (S) to Start,and swing the propeller." << endl;
cin >> startPause;
cout << "LED is On\n";
while (AccelerometerSensor != flyLevel) {
AccelerometerSensor++;
}
cout << "Flying session Started! Time Left:" << timeTofly << endl;
cout << "Eagle eye Operation Started!\n";
timeTofly = timeTofly / 2;
cout << "Crusing mode initiate Time Left:" << timeTofly << endl;
timeTofly = timeTofly / 2;
cout << "Free fly commenced Time Left:" << timeTofly << endl;
timeTofly = 0;
startPause = 'P';
} while ((startPause == 's') || (startPause == 'S'));
}
cout << "End!\nLED is Off";
return 0;
}
void manualMode() {
cout << "Enter drone speed (knot) \n";
cin >> speed;
cout << "Enter Time to fly: \n";
cin >> timeTofly;
cout << "Choose Operation: (1)Fully manual, (2)Normal Orientation, (3)Free orientation, (4)FPV racing, (5)All\n";
cin >> operation;
}
void defaultMode() {
int howtofly;
cout << "how to fly: (1)Circle, (2)Altitude Hold, (3)Free orientation";
cin >> howtofly;
switch (howtofly) {
case 1:
speed = 30;
timeTofly = 3;
break;
case 2:
speed = 40;
timeTofly = 3;
break;
case 3:
speed = 60;
timeTofly = 3;
break;
}
char name[25];
char id[5];
float m1, m2, m3, m4, m5;
ofstream outputFile("droneinfo.txt", ios::out);
cout << "Please enter object you want to record,drone id imei number and your 5 preferred video fps:\n";
cout << "\nPress <ctrl> + z to stop. \n";
while (cin >> id >> name >> m1 >> m2 >> m3 >> m4 >> m5)
{
outputFile << id << " " << name << " " << m1 << " " << m2 << " " << m3 << " " << m4 << " " << m5 << endl;
}
double fps = 0.0;
double Projectframerate = 0.0;
double actualframerate, out = 0;
Getdata(camrecord, Projectframerate);
calculate(camrecord, Projectframerate, actualframerate);
cout << "The actual frame rate is =" << actualframerate << " f/s\n";
}
void Getdata(double& camrecord, double& Projectframerate) {
cin >> camrecord;
cin >> Projectframerate;
cout << "Please enter\n Recording frame rate =" << camrecord << "f/s ,\ndesired frame rate="
<< Projectframerate << "f/s\n";
}
//-------------------//
void calculate(double& camrecord, double& Projectframerate, double& actualframerate) {
actualframerate = camrecord / Projectframerate;
}
//-------------------//
答案 0 :(得分:1)
因此,当您要输入变量并对其进行修改时,将引用作为参数使用。看着void Getdata(double& camrecord, double& Projectframerate)
,您说Getdata
取得了摄录机和项目帧速率,读取并修改了这些值,以便调用者可以使用新值。
看代码,看来Getdata
实际上并没有在读取输入值。因此存在不一致之处。
要与该方法的实现保持一致,方法Getdata
应该不接受任何参数-只能返回它们。现在,您不能返回两个参数,但是可以将它们打包到一个结构中并返回:
struct Data
{
double camrecord;
double Projectframerate;
};
Data Getdata();
Getdata
的定义可以是:
Data getData()
{
Data data;
cin >> data.camrecord;
cin >> data.Projectframerate;
cout << "Please enter\n Recording frame rate =" << data.camrecord << "f/s ,\ndesired frame rate="
<< data.Projectframerate << "f/s\n";
return data;
}
同样可以为calculate
完成。