Question

我正在尝试为我的API输出自定义异常：

app / Exceptions / Handler.php

public function render($request, Throwable $exception)
{
    if ($exception instanceof \Stripe\Exception\ApiErrorException) {
        return response()->json([
            'code' => $exception->getCode(),
            'message' => $exception->getMessage(),
        ]);
    }
    $response = $this->handleException($request, $exception);
    return $response;
}

public function handleException($request, Exception $exception)
{

    if ($exception instanceof MethodNotAllowedHttpException) {
        return $this->errorResponse('The specified method for the request is invalid', 405);
    }

    if ($exception instanceof NotFoundHttpException) {
        //return $this->errorResponse('The specified URL cannot be found', 404);

        dd('woo');
    }

    if ($exception instanceof HttpException) {
        return $this->errorResponse($exception->getMessage(), $exception->getStatusCode());
    }

    if (config('app.debug')) {
        return parent::render($request, $exception);            
    }
    return $this->errorResponse('Unexpected Exception. Try later', 500);

}

现在，我正在尝试通过查询控制器中不存在的ID来测试异常处理程序：

public function processCheckout(Request $request)
{    
    
    //Id 100 doesn't exist
    $plan = Plan::findOrFail(100);
    $user = $user = auth()->user();
    
    //If user has no subscriptions subscribe them to new plan
    if($user->subscriptions->count() === 0){
        $user->newSubscription($plan->name, $plan->stripe_plan_id)->create($request->payment_method['id']);

        //return response([], 201);
    }
}

我没有把laravel抛出异常放在处理程序中，而是一直没有异常发生。当我打开调试时，render方法似乎没有捕获到异常：

{
    "message": "No query results for model [App\\Plan] 100",
    "exception": "Symfony\\Component\\HttpKernel\\Exception\\NotFoundHttpException",
}

如何使它工作并实现自己的自定义消息？这是：

if ($exception instanceof NotFoundHttpException) {
    //return $this->errorResponse('The specified URL cannot be found', 404);

    dd('woo');
}

Answer 1

我知道了。由于某种原因，当模型不用于异常时，消息会指出它是NotFoundHttpException。如您在以上响应的这一部分中所见：

{
    "message": "No query results for model [App\\Plan] 100",
    "exception": "Symfony\\Component\\HttpKernel\\Exception\\NotFoundHttpException",
}

真正的异常是未找到模型异常：

在顶部

use Illuminate\Database\Eloquent\ModelNotFoundException;

在渲染方法中

if ($exception instanceof ModelNotFoundException) {
    return response()->json([
        'message' => 'Entry for '.str_replace('App\\', '', $exception->getModel()).' not found'], 404);
}

自定义异常处理程序不输出

1 个答案: