Question

我有一个要求，我要在雅典娜中查询并在邮递员中获取这样的api响应：

 {
            "id": "768ch23sgcjh",
            "gpsdate": "2019-04-06T13:02:08",
            "val1": "0.36233",
            "val2": "344",
            "loc": "{latitude=35.8374501, longitude=-49.0303646}"
        },
    {
            "id": "768ch23sgcjh",
            "gpsdate": "2019-04-06T13:02:08",
            "val1": ".22",
            "val2": "145",
            "loc": "{latitude=35.8374501, longitude=-49.0303646}"
        },
     {
            "id": "2453hsgdshgc",
            "gpsdate": "2019-04-06T13:02:08",
            "val1": "0.3030",
            "val2": "346",
            "loc": "{latitude=35.8374501, longitude=-79.0303646}"
        },

我想在框架中做一些喜欢的：

{
  "768ch23sgcjh" : [
     {
       "gpsdate":"2019-04-06T13:02:08",
       "val1": "0.36233",
       "val2": "344",
       "loc": "{latitude=35.8374501, longitude=-49.0303646}"
     }
     {
      "gpsdate":"2019-04-06T13:02:08",
       "val1": ".22",
       "val2": "145",
       "loc": "{latitude=35.8374501, longitude=-49.0303646}"
     }
  ]
  "2453hsgdshgc": [
     {
       "gpsdate":"2019-04-06T13:02:08",
       "val1": "0.3030",
       "val2": "346",
       "loc": "{latitude=35.8374501, longitude=-49.0303646}"
     }
 ]

}

我需要上面的格式。因此，基本上，如果对于给定的ID，有多组项目，则ID应该出现一次。

Answer 1

let inputArray = [{
		"id": "768ch23sgcjh",
		"gpsdate": "2019-04-06T13:02:08",
		"val1": "0.36233",
		"val2": "344",
		"loc": "{latitude=35.8374501, longitude=-49.0303646}"
	},
	{
		"id": "768ch23sgcjh",
		"gpsdate": "2019-04-06T13:02:08",
		"val1": ".22",
		"val2": "145",
		"loc": "{latitude=35.8374501, longitude=-49.0303646}"
	},
	{
		"id": "2453hsgdshgc",
		"gpsdate": "2019-04-06T13:02:08",
		"val1": "0.3030",
		"val2": "346",
		"loc": "{latitude=35.8374501, longitude=-79.0303646}"
	}
]

let outputArray = {};
for (let item of inputArray) {
	if (!outputArray[item.id]) {
		outputArray[item.id] = [{
			gpsdate: item.gpsdate,
			val1: item.val1,
			val2: item.val2,
			loc: item.loc
		}]
	} else {
		outputArray[item.id].push({
			gpsdate: item.gpsdate,
			val1: item.val1,
			val2: item.val2,
			loc: item.loc
		})
	}

}
console.log(outputArray);

Answer 2

您可以使用array#reduce对基于id的对象进行分组。

const arr = [{ "id": "768ch23sgcjh", "gpsdate": "2019-04-06T13:02:08", "val1": "0.36233", "val2": "344", "loc": "{latitude=35.8374501, longitude=-49.0303646}" }, { "id": "768ch23sgcjh", "gpsdate": "2019-04-06T13:02:08", "val1": ".22", "val2": "145", "loc": "{latitude=35.8374501,longitude=-49.0303646}" }, { "id": "2453hsgdshgc", "gpsdate": "2019-04-06T13:02:08", "val1": "0.3030", "val2": "346", "loc": "{latitude=35.8374501, longitude=-79.0303646}" }],
      result = arr.reduce((r, {id, ...rest}) => {
        r[id] = r[id] || [];
        r[id].push({...rest});
        return r;
      },{});
console.log(result);

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从node.js中的json对象创建嵌套的json对象

2 个答案: