Question

如何通过分隔符拆分字符串，但如果它被转义则不能？例如，我有一个字符串：

1|2\|2|3\\|4\\\|4

分隔符为|，转义分隔符为\|。此外，我想忽略转义的反斜杠，因此在\\|中，|仍然是分隔符。

所以使用上面的字符串，结果应该是：

[0] => 1
[1] => 2\|2
[2] => 3\\
[3] => 4\\\|4

Answer 1

使用黑暗魔法：

$array = preg_split('~\\\\.(*SKIP)(*FAIL)|\|~s', $string);

\\\\.匹配后跟字符的反斜杠，(*SKIP)(*FAIL)跳过它，\|匹配您的分隔符。

Answer 2

而不是split(...)，IMO更直观地使用某种类似于词法标记器的“扫描”功能。在PHP中，它将是preg_match_all函数。你只是说你想匹配：

\或|
或\后跟\或|
至少重复一次＃1或＃2

以下演示：

$input = "1|2\\|2|3\\\\|4\\\\\\|4";
echo $input . "\n\n";
preg_match_all('/(?:\\\\.|[^\\\\|])+/', $input, $parts);
print_r($parts[0]);

将打印：

1|2\|2|3\\|4\\\|4

Array
(
    [0] => 1
    [1] => 2\|2
    [2] => 3\\
    [3] => 4\\\|4
)

Answer 3

最近我设计了一个解决方案：

$array = preg_split('~ ((?<!\\\\)|(?<=[^\\\\](\\\\\\\\)+)) \| ~x', $string);

但黑魔法解决方案仍然快三倍。

Answer 4

对于未来的读者，这是一个通用的解决方案。它基于NikiC与(*SKIP)(*FAIL)：

的想法

function split_escaped($delimiter, $escaper, $text)
{
    $d = preg_quote($delimiter, "~");
    $e = preg_quote($escaper, "~");
    $tokens = preg_split(
        '~' . $e . '(' . $e . '|' . $d . ')(*SKIP)(*FAIL)|' . $d . '~',
        $text
    );
    $escaperReplacement = str_replace(['\\', '$'], ['\\\\', '\\$'], $escaper);
    $delimiterReplacement = str_replace(['\\', '$'], ['\\\\', '\\$'], $delimiter);
    return preg_replace(
        ['~' . $e . $e . '~', '~' . $e . $d . '~'],
        [$escaperReplacement, $delimiterReplacement],
        $tokens
    );
}

试一试：

// the base situation:
$text = "asdf\\,fds\\,ddf,\\\\,f\\,,dd";
$delimiter = ",";
$escaper = "\\";
print_r(split_escaped($delimiter, $escaper, $text));

// other signs:
$text = "dk!%fj%slak!%df!!jlskj%%dfl%isr%!%%jlf";
$delimiter = "%";
$escaper = "!";
print_r(split_escaped($delimiter, $escaper, $text));

// delimiter with multiple characters:
$text = "aksd()jflaksd())jflkas(('()j()fkl'()()as()d('')jf";
$delimiter = "()";
$escaper = "'";
print_r(split_escaped($delimiter, $escaper, $text));

// escaper is same as delimiter:
$text = "asfl''asjf'lkas'''jfkl''d'jsl";
$delimiter = "'";
$escaper = "'";
print_r(split_escaped($delimiter, $escaper, $text));

输出：

Array
(
    [0] => asdf,fds,ddf
    [1] => \
    [2] => f,
    [3] => dd
)
Array
(
    [0] => dk%fj
    [1] => slak%df!jlskj
    [2] => 
    [3] => dfl
    [4] => isr
    [5] => %
    [6] => jlf
    )
Array
(
    [0] => aksd
    [1] => jflaksd
    [2] => )jfl'kas((()j
    [3] => fkl()
    [4] => as
    [5] => d(')jf
)
Array
(
    [0] => asfl'asjf
    [1] => lkas'
    [2] => jfkl'd
    [3] => jsl
)

注意：存在理论级别问题：implode('::', ['a:', ':b'])和implode('::', ['a', '', 'b'])会产生相同的字符串：'a::::b'。 Imploding也是一个有趣的问题。

Answer 5

正则表达式非常缓慢。一种更好的方法是在拆分之前从字符串中删除转义字符，然后将它们放回：

$foo = 'a,b|,c,d||,e';

function splitEscaped($str, $delimiter,$escapeChar = '\\') {
    //Just some temporary strings to use as markers that will not appear in the original string
    $double = "\0\0\0_doub";
    $escaped = "\0\0\0_esc";
    $str = str_replace($escapeChar . $escapeChar, $double, $str);
    $str = str_replace($escapeChar . $delimiter, $escaped, $str);

    $split = explode($delimiter, $str);
    foreach ($split as &$val) $val = str_replace([$double, $escaped], [$escapeChar, $delimiter], $val);
    return $split;
}

print_r(splitEscaped($foo, ',', '|'));

分裂为'，'但是如果用“|”进行转义则不会。它还支持双重转义，因此“||”成为一个单一的“|”拆分发生后：

Array ( [0] => a [1] => b,c [2] => d| [3] => e )

按分隔符拆分字符串，但如果它已转义则不会

5 个答案: