我有一个熊猫数据框,我想将“ F”列移到“ B”列之后。有办法吗?
A B C D E F
0 7 1 8 1 6
1 8 2 5 8 5 8
2 9 3 6 8 5
3 1 8 1 3 4
4 6 8 2 5 0 9
5 2 N/A 1 3 8
df2
A B F C D E
0 7 1 6 8 1
1 8 2 8 5 8 5
2 9 3 5 6 8
3 1 4 8 1 3
4 6 8 9 2 5 0
5 2 8 N/A 1 3
所以它最终应该看起来像df2。 提前致谢。
答案 0 :(得分:6)
在df.insert
处获得B的位置后,您可以尝试df.pop
+ get_loc
df.insert(df.columns.get_loc("B")+1,"F",df.pop("F"))
print(df)
A B F C D E
0 7.0 1 6.0 NaN 8 1.0
1 8.0 2 8.0 5.0 8 5.0
2 9.0 3 5.0 6.0 8 NaN
3 1.0 8 NaN 1.0 3 4.0
4 6.0 8 9.0 2.0 5 0.0
5 NaN 2 8.0 NaN 1 3.0
答案 1 :(得分:3)
另一种极简主义(非常具体!)方法:
<Switch>
<Route key="Home" path="/home" component={Home} />
<Route key="PolicyPlan-create" path="/PolicyPlan/create" component={PolicyPlanCreatePage} />
{/* <Route key="PolicyPlan-list" path="/PolicyPlan" component={PolicyPlanListPage} /> */}
<Route key="PolicyPlan-list" path="/PolicyPlan/list" component={PolicyPlanListPage} />
<Route key="PolicyPlan-edit" path="/PolicyPlan/edit/:id" component={PolicyPlanCreatePage} />
<Route key="cardDesign" path="/cardDesign" component={cardDesign} />
<Route key="Admin-create" path="/admin/create" component={RegisterPage} />
</Switch>