Question

我有两个数组。一种是想法，另一种是评论者。

['idea1', 'idea2', 'idea3', 'idea4', 'idea5', 'idea6', 'idea7']
['reviewer1', 'reviewer2', 'reviewer3', 'reviewer4']

我需要从以上两个数组生成一个数据对象，以将其馈送到表中。在生成对象时需要帮助。

[ {
   fields: {
     "Idea": "idea1",
     "Reviewer": "reviewer1"
   }, fields: {
     "Idea": "idea2",
     "Reviewer": "reviewer2"
   }, fields: {
     "Idea": "idea3",
     "Reviewer": "reviewer3"
   },  fields: {
     "Idea": "idea4",
     "Reviewer": "reviewer4"
   },  fields: {
     "Idea": "idea5",
     "Reviewer": "reviewer1"
   },  fields: {
     "Idea": "idea6",
     "Reviewer": "reviewer2"
   },  fields: {
     "Idea": "idea7",
     "Reviewer": "reviewer3"
   }, 
}]

一个评论者将被分配给多个创意，但是对于任何一个创意，只有一个评论者。

Answer 1

类似这样的东西：

const idea = ['idea1', 'idea2', 'idea3', 'idea4', 'idea5', 'idea6', 'idea7']
const reviewer = ['reviewer1', 'reviewer2', 'reviewer3', 'reviewer4']

let ctr =0;
const res = idea.reduce((acc, val)=>{
 ctr= ctr=== reviewer.length? 0 : ctr;
 acc = [...acc, {"fields":{
  "idea": val,
  "reviewer": reviewer[ctr++]
 }}];
  return acc
},[])

console.log(res)

不需要变异ctr的一种更好，更简单的方法是

var idea = ['idea1', 'idea2', 'idea3', 'idea4', 'idea5', 'idea6', 'idea7'];
var reviewer = ['reviewer1', 'reviewer2', 'reviewer3', 'reviewer4'];

var res = idea.map((idea, i) => {
  return {
    fields: {
      idea,
      reviewer: reviewer[i % reviewer.length]
    }
  }
});

console.log(res)

从多个数组创建嵌套对象

1 个答案: