Question

我已经阅读了该站点上有关StaleElementReferenceException的几篇文章，并且知道此错误是由元素不再位于站点的DOM中引起的。我想做的是单击此网页上的底部链接以继续查看下一页的清单。我已经尝试了几种解决此异常的方法，但没有找到任何可行的方法。这是我尝试过的代码示例，以及我认为可以完成的代码。

driver = webdriver.Chrome(r'C:\Users\Hank\Desktop\chromedriver_win32\chromedriver.exe')
driver.get('https://steamcommunity.com/market/listings/440/Unusual%20Old%20Guadalajara')
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait as wait
from selenium.webdriver.support.expected_conditions import presence_of_element_located
from selenium.webdriver.common.action_chains import ActionChains
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import StaleElementReferenceException
action = ActionChains(driver)
page_links = wait(driver, 10).until(EC.presence_of_all_elements_located((By.CSS_SELECTOR, '[class^=market_paging_pagelink]')))
try:
    action.move_to_element(page_links[1]).click().perform()
except StaleElementReferenceException as Exception:
    print("Exception received, trying again")
    time.sleep(5)
    page_links = wait(driver, 10).until(EC.presence_of_all_elements_located((By.CSS_SELECTOR, '[class^=market_paging_pagelink]')))
    action.move_to_element(page_links[1]).click().perform()

我希望该代码段将尝试移至底部的元素，单击它，或返回错误消息，然后再次尝试，第二次成功。相反，代码只是再次引发错误。如果我的问题已得到解答，请引导我到相关链接。谢谢！

Answer 1

我通常采用的方法是单击“下一页”，直到该按钮被禁用/不可见。

这是一个基于您的页面的有效示例。显然，您应该执行while循环中的所有相关操作；为了示例，我选择捕获价格。

url="https://steamcommunity.com/market/listings/440/Unusual%20Old%20Guadalajara"
driver.get(url)

next_button=wait(driver, 10).until(EC.presence_of_element_located((By.ID,'searchResults_btn_next')))

# capture the start value from "Showing x-xx of 22 results"
#need this to check against later
ref_val=wait(driver, 10).until(EC.presence_of_element_located((By.ID,'searchResults_start'))).text

while next_button.get_attribute('class') == 'pagebtn':
    next_button.click()
    #wait until ref_val has changed
    wait(driver, 10).until(lambda driver: wait(driver, 10).until(EC.presence_of_element_located((By.ID,'searchResults_start'))).text != ref_val)

    # ====== Do whatever relevant here =============================
    page_num=wait(driver, 10).until(EC.presence_of_element_located((By.CSS_SELECTOR,'.market_paging_pagelink.active'))).text
    print(f"Prices from page {page_num}")
    prices = wait(driver, 10).until(EC.presence_of_all_elements_located(
        (By.XPATH, ".//span[@class='market_listing_price market_listing_price_with_fee']")))
    for price in prices:
        print(price.text)
    #================================================================

    #get the new reference value
    ref_val = wait(driver, 10).until(EC.presence_of_element_located((By.ID, 'searchResults_start'))).text

硒中规避陈旧元素异常

1 个答案: