requestSpec.addMultiPart(new MultiPartSpecBuilder(note).controlName("note").charset(Charsets.UTF_8).build());
Ergebnis:
现在我只需要第一行“ first_name” =“ Eins”,因为“ yes”等于“ no”。 我怎样才能做到这一点statemant? 是=否...不起作用。
感谢您的帮助
答案 0 :(得分:3)
我将查询表述为:
select
ev.id as event_slot_id,
u.first_name,
u.id AS user_id,
sum(next_round = 1) AS yes,
sum(next_round = 2) AS no
from event_slots as ev
inner join audition_card_values as acv
on acv.user_id = ev.selected_by_user_id
left join users as u
on u.id = ev.selected_by_user_id
where e.event_id = 1
group by ev.id, u.first_name, u.id
having sum(next_round = 1) = sum(next_round = 2)
理论上:
sum()
中的条件表达式可以简化
您可以使用having
子句进行过滤; MySQL还支持重用select
子句的having
子句中定义的别名,因此您可以这样拼写:having yes = no
-但我更喜欢重复条件表达式,因为这是标准SQL
在left join
上的audition_card_values
之后,在连接列上的where ... is not null
可以重写为简单的inner join
我修复了您的group by
子句; select
子句中的每个未聚合列都必须出现在group by
子句中