棋盘界面。无法移除孩子。有什么建议?

时间:2011-06-04 17:17:28

标签: actionscript-3 flash-cs4 removechild

您好 我正在创建一个棋盘,你可以移动棋子。目前我正在开车,编码如下。我知道它不优雅,可能是最低效的代码,但这是我的actionscript 3.0生活的第2天,我有点像初学者。无论如何,事情就是,当你点击下面的代码时,下面的代码就会找出可行的方法。然后在那些地方出现绿色方块。然后你可以按下这些绿色方块,然后车就会移动到那里。

好的,现在问题。广场不会消失。当我点击其中一个并且车将移动到那里时,我希望它们全部被删除。

我尝试过removeChild(),但由于这种情况发生在另一个函数中,因此无效。因此,如果您非常善于查看代码并提出解决方案,我们非常感谢您的帮助。

亲切的问候Emile

https://picasaweb.google.com/109156245246626370734/Jun42011?authkey=Gv1sRgCMy4v_b01aikzAE&feat=directlink

import flash.display.Sprite
import flash.events.MouseEvent
import flash.text.TextField;
import flash.geom.Point;
import caurina.transitions.*

myPoint.addEventListener(MouseEvent.MOUSE_DOWN, startMove);

function startMove(evt:MouseEvent) {

    var boxNum:int = Math.floor(myPoint.y/100)+1;
    for (var i:int = 1; i <boxNum; i++) {
        var box:Ball = new Ball();
        box.x = myPoint.x;
        box.y = myPoint.y - i * box.height;
        addChild(box);
        Tweener.addTween(box, {alpha:0.5});
                box.buttonMode = true;
                box.addEventListener(MouseEvent.ROLL_OVER, onOver,
                                     false, 0, true);
                box.addEventListener(MouseEvent.ROLL_OUT, onOut,
                                     false, 0, true);
                box.addEventListener(MouseEvent.MOUSE_DOWN, onclick);
        }
    var boxNum1:int = Math.floor((800-myPoint.y)/100)+1;
    for (var i:int = 1; i <boxNum1; i++) {
        var box1:Ball = new Ball();
        box1.x = myPoint.x;
        box1.y = myPoint.y + i * box.height;
        addChild(box1);
        Tweener.addTween(box1, {alpha:0.5});
                box1.buttonMode = true;

                box1.addEventListener(MouseEvent.ROLL_OVER, onOver,
                                     false, 0, true);
                box1.addEventListener(MouseEvent.ROLL_OUT, onOut,
                                     false, 0, true);
                box1.addEventListener(MouseEvent.CLICK, onclick);
    }
    var boxNum2:int = Math.floor(myPoint.x/100)+1;
    for (var i:int = 1; i <boxNum2; i++) {
        var box2:Ball = new Ball();
        box2.x = myPoint.x - i * box.height;
        box2.y = myPoint.y;

        addChild(box2);
        Tweener.addTween(box2, {alpha:0.5});
                box2.buttonMode = true;
                box2.addEventListener(MouseEvent.ROLL_OVER, onOver,
                                     false, 0, true);
                box2.addEventListener(MouseEvent.ROLL_OUT, onOut,
                                     false, 0, true);
                box2.addEventListener(MouseEvent.CLICK, onclick);
    }
    var boxNum3:int = Math.floor((800-myPoint.x)/100)+1;
    for (var i:int = 1; i <boxNum3; i++) {
        var box3:Ball = new Ball();
        box3.x = myPoint.x + i * box.height;
        box3.y = myPoint.y;
        addChild(box3);
        Tweener.addTween(box3, {alpha:0.5});
        box3.buttonMode = true;
        box3.addEventListener(MouseEvent.ROLL_OVER, onOver, false, 0, true);
        box3.addEventListener(MouseEvent.ROLL_OUT, onOut, false, 0, true);
        box3.addEventListener(MouseEvent.CLICK, onclick);
    }
}

function onOver(evt:Event):void {
    var box:MovieClip = MovieClip(evt.target);
    addChild(box)
    box.scaleX = box.scaleY = 1.1;
}

function onOut(evt:Event):void {
    evt.target.scaleX = evt.target.scaleY = 1;
}

function onclick(Event:MouseEvent):void {
    var xcod:int = Math.ceil(mouseX/100)*100-50;
    var ycod:int = Math.ceil(mouseY/100)*100-50;
    Tweener.addTween(myPoint, {x:xcod, y:ycod, time:1, transition:"linear"});
}

2 个答案:

答案 0 :(得分:1)

alxx的回答是正确的,你不需要为他们保留一个特殊的清单。使用Array保存引用的另一种方法是:

var boxes:Array = new Array();

function startMove(evt:MouseEvent):void {
   ...
   var box:Ball = new Ball();
   addChild(box);
   boxes.push(box);
   ...
   var box1:Ball = new Ball();
   addChild(box1);
   boxes.push(box1);
   ...
}

function onClick(evt:MouseEvent):void {
   for each (var box:Ball in boxes) {
      removeChild(box);
   }
   boxes = new Array();
}

答案 1 :(得分:0)

您可以将临时突出显示放在单独的Sprite中。然后你的董事会看起来如下:
舞台儿童:基板,亮点,棋子,按顺序 当您需要移除突出显示时,您可以使用numChildrengetChildAt重复突出显示的子项,并在每个项目上调用removeChild,您甚至不需要特殊列表。