使用以下查询：
select b1.Name DrBook, c1.Name DrControl, b2.Name CrBook, c2.Name CrControl, tn.Amount
from Transactions tn
left join Books b1 on b1.Id = tn.DrBook
left join Books b2 on b2.Id = tn.CrBook
left join ControlLedgers c1 on c1.Id = tn.DrControl
left join ControlLedgers c2 on c2.Id = tn.CrControl
我得到了资产负债表的这个结果集：
+---------------------+-----------+---------------------+-----------+--------+
| DrBook | DrControl | CrBook | CrControl | Amount |
+---------------------+-----------+---------------------+-----------+--------+
| Current Assets | Cash | Fund | Initial | 100000 |
| Current Assets | Cash | Fund | Initial | 100000 |
| Current Assets | Cash | Fund | Initial | 100000 |
| Current Assets | Cash | Fund | Initial | 100000 |
| Current Assets | Cash | Fund | Initial | 100000 |
| Expenses | Foods | Current Liabilities | Payables | 10000 |
| Current Liabilities | Payables | Current Assets | Cash | 5000 |
+---------------------+-----------+---------------------+-----------+--------+
要在我的应用程序中显示资产负债表，我现在正在做的是发出两个查询并获得两个结果集，如下所示：
查询1：
select b1.Name DrBook, c1.Name DrControl, SUM(tn.Amount) Amount
from Transactions tn
left join Books b1 on b1.Id = tn.DrBook
left join ControlLedgers c1 on c1.Id = tn.DrControl
group by DrBook, DrControl
结果集1：
+---------------------+-----------+--------+
| DrBook | DrControl | Amount |
+---------------------+-----------+--------+
| Current Assets | Cash | 500000 |
| Expenses | Foods | 10000 |
| Current Liabilities | Payables | 5000 |
+---------------------+-----------+--------+
查询2：
select b1.Name CrBook, c1.Name CrControl, SUM(tn.Amount) Amount
from Transactions tn
left join Books b1 on b1.Id = tn.CrBook
left join ControlLedgers c1 on c1.Id = tn.CrControl
group by CrBook, CrControl
结果集2：
+---------------------+-----------+--------+
| CrBook | CrControl | Amount |
+---------------------+-----------+--------+
| Current Assets | Cash | 5000 |
| Current Liabilities | Payables | 10000 |
| Fund | Initial | 500000 |
+---------------------+-----------+--------+
，如果结果集2是资产或费用（在此情况下为流动资产），则从结果集1中减去结果集2；如果结果是负债，收入或基金（在此情况下为流动负债和收入），则从结果集2中减去结果集1。资金）以获得最终结果集，例如：
+---------------------+---------------+---------+
| Book | ControlLedger | Balance |
+---------------------+---------------+---------+
| Current Assets | Cash | 495000 |
| Expenses | Food | 10000 |
| Current Liabilities | Payables | 5000 |
| Fund | Initial | 500000 |
+---------------------+---------------+---------+
我已经尝试过一些case语句来通过sql查询获得最终结果集，而不是在应用程序代码中手动计算，但那些行不通！
编辑
这是表格的定义：
CREATE TABLE "Transactions"(
"Id" INTEGER NOT NULL,
"Date" TEXT NOT NULL,
"DrBook" INTEGER NOT NULL,
"CrBook" INTEGER NOT NULL,
"DrControl" INTEGER NOT NULL,
"CrControl" INTEGER NOT NULL,
"DrLedger" INTEGER,
"CrLedger" INTEGER,
"DrSubLedger" INTEGER,
"CrSubLedger" INTEGER,
"DrPartyGroup" INTEGER,
"CrPartyGroup" INTEGER,
"DrParty" INTEGER,
"CrParty" INTEGER,
"DrMember" INTEGER,
"CrMember" INTEGER,
"Amount" INTEGER NOT NULL,
"Narration" TEXT,
FOREIGN KEY("DrBook") REFERENCES "Books"("Id"),
FOREIGN KEY("CrBook") REFERENCES "Books"("Id"),
FOREIGN KEY("DrControl") REFERENCES "ControlLedgers"("Id"),
FOREIGN KEY("CrControl") REFERENCES "ControlLedgers"("Id"),
FOREIGN KEY("DrLedger") REFERENCES "Ledgers"("Id"),
FOREIGN KEY("CrLedger") REFERENCES "Ledgers"("Id"),
FOREIGN KEY("DrSubLedger") REFERENCES "SubLedgers"("Id"),
FOREIGN KEY("CrSubLedger") REFERENCES "SubLedgers"("Id"),
FOREIGN KEY("DrPartyGroup") REFERENCES PartyGroups("Id"),
FOREIGN KEY("CrPartyGroup") REFERENCES PartyGroups("Id"),
FOREIGN KEY("DrParty") REFERENCES "Parties"("Id"),
FOREIGN KEY("CrParty") REFERENCES "Parties"("Id"),
FOREIGN KEY("DrMember") REFERENCES "Members"("Id"),
FOREIGN KEY("CrMember") REFERENCES "Members"("Id")
);
我为每本日记插入一行，其中包含借方，贷方和金额信息。我没有Dr / CrProduct或Dr / CrServices，因为它是为个人和家庭的簿记和会计设计的。
例如，要从A先生那里购买食物，我会通过（1）：
Expenses -> Food -> Rice -> Fine Rice A/c Dr. 10000
Current Liabilities -> Payables A/C Cr. 10000
如果是赊帐的，并且当购买金额以现金支付时，我会通过（2）：
Current Liabilities -> Payables A/C Dr. 10000
Current Assets -> Cash -> In Hand -> Emon A/c Cr. 10000
在表中它将变为：
+----+------------+--------+--------+-----------+-----------+----------+----------+-------------+-------------+--------------+--------------+---------+---------+----------+----------+--------+----------------+
| Id | Date | DrBook | CrBook | DrControl | CrControl | DrLedger | CrLedger | DrSubLedger | CrSubLedger | DrPartyGroup | CrPartyGroup | DrParty | CrParty | DrMember | CrMember | Amount | Narration |
+----+------------+--------+--------+-----------+-----------+----------+----------+-------------+-------------+--------------+--------------+---------+---------+----------+----------+--------+----------------+
| 3 | 2020-06-15 | 3 | 5 | 9 | 18 | 2 | | 2 | | | 4 | | 1 | | | 10000 | Some Narration |
| 3 | 2020-06-15 | 5 | 2 | 18 | 7 | | 1 | | 1 | 4 | | 1 | | | | 10000 | |
+----+------------+--------+--------+-----------+-----------+----------+----------+-------------+-------------+--------------+--------------+---------+---------+----------+----------+--------+----------------+
这是第一行的快速剖析：
+--------------+----------------+---------------------+
| Columns | Values | Mappings |
+--------------+----------------+---------------------+
| DrBook | 3 | Expenses |
| CrBook | 5 | Current Liabilities |
| DrControl | 9 | Food |
| CrControl | 18 | Payables |
| DrLedger | 2 | Rice |
| DrSubLedger | 2 | Fine Rice |
| CrPartyGroup | 4 | Groceries |
| CrParty | 1 | Mr. A |
| Amount | 10000 | |
| Narration | Some Narration | |
+--------------+----------------+---------------------+
答案 0 :(得分：0)
不确定以下是否是唯一方法：
with t1(Id, Book, Control, Amount) as (
select tn.DrBook, b1.Name, c1.Name, sum(tn.Amount)
from Transactions tn
left join Books b1 on b1.Id = tn.DrBook
left join ControlLedgers c1 on c1.Id = tn.DrControl
group by DrBook, DrControl
),
t2 as (
select tn.CrBook, b1.Name, c1.Name, -1*sum(tn.Amount)
from Transactions tn
left join Books b1 on b1.Id = tn.CrBook
left join ControlLedgers c1 on c1.Id = tn.CrControl
group by CrBook, CrControl
),
t3 as (
select * from t1 union all select * from t2
)
select Book, Control,
case when Id <=3 then sum(Amount)
else -1*sum(Amount) end Balance
from t3 group by Book, Control order by Id
它产生的正是我所期望的：
+---------------------+----------+---------+
| Book | Control | Balance |
+---------------------+----------+---------+
| Current Assets | Cash | 495000 |
| Current Liabilities | Payables | 5000 |
| Expenses | Foods | 10000 |
| Fund | Initial | 500000 |
+---------------------+----------+---------+