Question

我正在尝试开发一个子手作为一项任务，并且无法从文本文件中获得一个随机单词（该单词有各种单词，每个单词都用空格分隔）。我已经编写了一个代码以获取一个随机单词，但无法选择一个单词并将其替换为示例字符串（String w =“ this”;），该字符串已包含在“ Function（）”中。

 public String randomWord(String wordran) {

    try {
        BufferedReader reader = new BufferedReader(new FileReader("C:\\Users\\Admin\\Documents\\NetBeansProjects\\Main\\words.txt"));
        String line = reader.readLine();
        List<String> words = new ArrayList<String>();
        while (line != null) {
            String[] wordline = line.split(" ");
            for (String word : wordline) {
                words.add(word);
            }
            Random rand = new Random();
            String randomWord1 = words.get(rand.nextInt(words.size()));
            //System.out.println("rand word : " + randomWord1);

        }
        reader.close();

    } catch (Exception e) {

    }
    return wordran;


}


   public void function(){

    int numGuesses = 10;
    String w = randomWord();

    String[] word = w.split("");
    ArrayList< String> wList = new ArrayList<>(Arrays.asList(word));
    ArrayList< String> wAnswer = new ArrayList< String>(wList.size());
    for (int i = 0; i < wList.size(); i++) {
        wAnswer.add("_ ");
    }
    int left = wList.size();
    Scanner scanner = new Scanner(System.in);
    boolean notDone = true;
    ArrayList< String> lettersGuessed = new ArrayList< String>();

    while (notDone) {
        System.out.println();
        String sOut = "";

        List< String> lettersLeft = getRemainingLetters(lettersGuessed);
        for (String s : lettersLeft) {
            sOut += s + " ";
        }
        System.out.println("Letters Left: " + sOut);

        sOut = "";
        for (int i = 0; i < wList.size(); i++) {
            sOut += wAnswer.get(i);
        }
        System.out.println(sOut + " Guesses left:" + numGuesses);
        System.out.print("Enter a letter(* exit): ");
        String sIn = scanner.next();
        numGuesses--;
        if (sIn.equals("*")) {
            break;
        }
        lettersGuessed.add(sIn);
        for (int i = 0; i < wList.size(); i++) {
            if (sIn.equals(wList.get(i))) {
                wAnswer.set(i, sIn);
                left--;
            }
        }
        if (left == 0) {
            System.out.println("Congradulations you guessed it!");
            break;
        }
        if (numGuesses == 0) {
            System.out.println("You failed...:(");
            break;
        }

    }

}

public static void main(String[] args) throws IOException {
    Main ma = new Main();

    ma.function();

    loadWords();

   // ma.randomWord();

}

Answer 1

您的代码存在三个问题：

您不需要传递参数String wordran来存储随机单词。有用的参数可以是String path，通过它您可以将文件的路径传递给函数。
您错过了在循环中读取文件内容的操作。您只读了第一行。
您尚未返回通过应用Random#nextInt计算出的随机词。

另一方面，建议您使用try-with-resources语法摆脱显式关闭BufferedReader的情况。

下面给出的是包含这些注释的正确代码：

import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Random;

public class Main {
    public static void main(String[] args) throws IOException {
        // Test
        System.out.println(getRandomWord("C:\\Users\\Admin\\Documents\\NetBeansProjects\\Main\\words.txt"));
    }

    public static String getRandomWord(String path) throws IOException {
        List<String> words = new ArrayList<String>();
        try (BufferedReader reader = new BufferedReader(new FileReader(path))) {
            String line;
            while ((line = reader.readLine()) != null) {
                String[] wordline = line.split("\\s+");
                for (String word : wordline) {
                    words.add(word);
                }
            }
        }
        Random rand = new Random();
        return words.get(rand.nextInt(words.size()));
    }
}

从文本文件中选择一个随机词

1 个答案: