Question

当我将以下依赖项添加到代码中时，触发以下错误

'--packages org.apache.spark:spark-sql-kafka-0-10_2.11:2.2.0,org.apache.spark:spark-streaming-kafka-0-8-assembly_2.11:2.1.1'

下面是代码，

from pyspark.sql import SparkSession, Row
from pyspark.context import SparkContext
from kafka import KafkaConsumer
import os

os.environ['PYSPARK_SUBMIT_ARGS'] = '--packages org.apache.spark:spark-sql-kafka-0-10_2.11:2.2.0,org.apache.spark:spark-streaming-kafka-0-8-assembly_2.11:2.1.1'


sc = SparkContext.getOrCreate()
spark = SparkSession(sc)

df = spark \
  .read \
  .format("kafka") \
  .option("kafka.bootstrap.servers", "localhost:9092") \
  .option("subscribe", "Jim_Topic") \
  .load()
df.selectExpr("CAST(key AS STRING)", "CAST(value AS STRING)")

下面是错误

错误：缺少应用程序资源。

用法：spark-submit [选项] [app自变量] 用法：spark-submit --kill [提交ID] --master [spark：// ...] 用法：spark-submit --status [提交ID] --master [spark：// ...] 用法：spark-submit run-example [options] example-class [example args]

Answer 1

您还需要提供python文件的名称。

os.environ['PYSPARK_SUBMIT_ARGS'] = '--packages org.apache.spark:spark-sql-kafka-0-10_2.11:2.2.0,org.apache.spark:spark-streaming-kafka-0-8-assembly_2.11:2.1.1 your_python_file.py'

或者，更好的方法是：

conf = SparkConf().set("spark.jars", "/path/to/your/jar")
sc = SparkContext(conf=conf)

PySpark Kafka错误：缺少应用程序资源

1 个答案: