Question

我希望从字符串中获取换行符\n之后的所有值。我怎样才能获得这些价值观？

Answer 1

试试这个：

NSString *substring = nil;
NSRange newlineRange = [yourString rangeOfString:@"\n"];
if(newlineRange.location != NSNotFound) {
  substring = [yourString substringFromIndex:newlineRange.location];
}

Answer 2

查看方法componentsSeparatedByString here。

参考文献中的一个简单示例：

NSString *list = @"Norman, Stanley, Fletcher";
NSArray *listItems = [list componentsSeparatedByString:@", "];

这将生成一个NSArray，其中的字符串分隔为：{ @"Norman", @"Stanley", @"Fletcher" }

Answer 3

这是类似的函数，它通过分隔符拆分字符串，并返回带有两个修剪值的数组。

NSArray* splitStrByDelimAndTrim(NSString *string, NSString *delim)
{
    NSRange range = [string rangeOfString: delim];

    NSString *first;
    NSString *second;

    if(range.location == NSNotFound)
    {
        first = @"";
        second = string;
    }
    else
    {
        first = [string substringToIndex: range.location];
        first = [first stringByTrimmingCharactersInSet: [NSCharacterSet whitespaceCharacterSet]];
        second = [string substringFromIndex: range.location + 1];
        second = [second stringByTrimmingCharactersInSet: [NSCharacterSet whitespaceCharacterSet]];
    }

    return [NSArray arrayWithObjects: first, second, nil];
}

如何获得“\ n”字符后的值？

3 个答案: