在两个日期时间熊猫之间获取datetime64 [ns]

Question

我正在尝试在特定日期时间内提取行。我在做什么错了？

import pandas as pd

df = pd.DataFrame({'year': [2015, 2016, 2017, 2016],
                   'month': [2, 3, 4, 6],
                   'day': [4, 5, 4, 3]})

df = pd.to_datetime(df)
df = df.to_frame(name='test')

start_date = pd.Timestamp(2016,1,1)
end_date = pd.Timestamp(2017, 5, 1)
start_date = pd.to_datetime(start_date)
end_date = pd.to_datetime(end_date)

print (start_date)
print (end_date)

print (df[df['test'] > start_date & df['test'] < end_date])

Answer 1

由于运营商的优先级，缺少()：

print (df[(df['test'] > start_date) & (df['test'] < end_date)])

或使用Series.between：

print (df[(df['test'].between(start_date, end_date, inclusive=False)])