Question

我有两个列表

list1 = [1,2,3,4,5,6,'NO DATA',8,9,10]
list2 = [0,0,0,0,0,0,7,0,0,0]

所以我需要将list1中的第7个元素从list2更改为第7个元素

我需要定义这个：

for x in list1:
    if x == 'NO DATA':

需要将{{1}的x[index]从list1更改为x[index]

我如何做到这一点？

所以我需要最终清单list2

Answer 1

一种相当简单的方法：

data:[
       {
  nr:1,
  user: [
      {
      firstName:'John',
      lastName: 'Doe'
      },
      {
      firstName:'Bill',
      lastName: 'White'
      }
       ]
       },
              {
  nr:2,
  user: [
      {
      firstName:'Carl',
      lastName: 'Doe'
      },
      {
      firstName:'Mike',
      lastName: 'Green'
      },
      {
      firstName:'Sarah',
      lastName: 'Doe'     
      }
       ]
       }, 
     ]
   ....  
     // object depend by how many fields user added in each nr

结果是：

list1 = [1,2,3,4,5,6,'NO DATA',8,9,10]
list2 = [0,0,0,0,0,0,7,0,0,0]


def get_item(x,y):
    if x == "NO DATA":
        return y
    return x

[get_item(x, y) for (x,y) in zip(list1, list2)]

Answer 2

请尝试：

$var->show_foo

Answer 3

list1 = [1,2,3,4,5,6,'NO DATA',8,9,10]
list2 = [0,0,0,0,0,0,7,0,0,0]

index=list1.index('NO DATA')

list3=list1[:index]+list2[index:index+1]+list1[index+1:]

Answer 4

  i=0
  for a,b in zip(x,y):
     if a=='No data':
            x[i]=b
     i+=1

将某些值从一个列表更改为另一个python

4 个答案: