scanf到struct不起作用

时间:2011-06-03 14:18:40

标签: c struct scanf

我有这个功能,我需要获取结构的坐标。 这些是结构:
// --------- ----------结构

typedef struct coordinates  
{
    int x_l;
    int y_l;
    int x_r;
    int y_r;
} Coordinates;

typedef struct field 
{
    char Id;
    Coordinates location;
    int area;
    int price;
} Field;

这是功能:

Field GetFieldFromUser(int cptr,Field *pf1)
{       
    //Field *pf
    int i=0;

    printf("\nPlease enter information for your new field:\n");
    printf("the Id of the field is 5 digit num between 00000-99999:\n");
    printf("The Id of the Field given Automatic by the system\n");


    pf1->Id= 0000+cptr;

    printf("\nThis is the ID for the new field: ");

    printf("id = %05d\n",pf1->Id);

    printf("\nPlease enter the coordinates of the top left of the field (press ' ' between the digits)\n");
    scanf("%d %d",pf1->location.x_l,pf1->location.y_l);
    fflush(stdin);
    printf("Please enter the coordinates of the lower right of the field (press ' ' between the digits)\n");
    scanf("%d %d",pf1->location.x_r,pf1->location.y_r);

    return *pf1;
}

现在在编译器把我扔出去的位置的scanf,我不知道为什么

有什么建议吗?

1 个答案:

答案 0 :(得分:5)

scanf("%d %d",pf1->location.x_l,pf1->location.y_l);

应该是

scanf("%d %d",&(pf1->location.x_l), &(pf1->location.y_l));

下一次scanf的逻辑相同。 scanf期望它可以写入的地址。你传递了它的值(可能是未初始化的值)。所以它试图写入一些未知的内存位置。