我有一个字典数组,sortArrayUsingComparator根据键对它们进行排序;
listPerc = [listItem sortedArrayUsingComparator: ^(id a, id b) {
NSString *first = [a objectForKey:@"perc"];
NSString *second = [b objectForKey:@"perc"];
return [first compare:second];
问题是这个键是一个数字,例如:1,10,15,17,2,23等。
它不计算数字的大小。
我怎么办?
答案 0 :(得分:18)
你不能像这样返回比较结果,
listPerc = [listItem sortedArrayUsingComparator: ^(id a, id b) {
int first = [[a objectForKey:@"perc"] intValue];
int second = [[b objectForKey:@"perc"] intValue];
if ( first < second ) {
return (NSComparisonResult)NSOrderedAscending;
} else if ( first > second ) {
return (NSComparisonResult)NSOrderedDescending;
} else {
return (NSComparisonResult)NSOrderedSame;
}
}
答案 1 :(得分:7)
@(Deepak Danduprolu)答案的简短方法
listPerc = [listItem sortedArrayUsingComparator: ^(id a, id b) {
NSNumber *first = @([[a objectForKey:@"perc"] intValue]);
NSNumber *second = @([[b objectForKey:@"perc"] intValue]);
return [first compare:second];
}
答案 2 :(得分:4)
将它们转换为NSNumber对象并进行比较。要么将它们存储为NSNumbers(首选方法),要么在比较时转换它们(较慢)。
将NSString转换为NSNumber可以通过以下方式完成:
NSNumberFormatter * f = [[NSNumberFormatter alloc] init];
[f setNumberStyle:NSNumberFormatterDecimalStyle];
NSNumber * myNumber = [f numberFromString:string];
[f release];
答案 3 :(得分:0)
也许你可以做这样的事情。
- (void)setPlaces:(NSArray *)places
{
if(_places != places)
{
_places = [places sortedArrayUsingComparator:^(id obj1, id obj2){
return [[obj1 objectForKey:FLICKR_PLACE_NAME] caseInsensitiveCompare:[obj2 objectForKey:FLICKR_PLACE_NAME]];
}];
[self.tableView reloadData];
}
}
我做了一些你和你之间的交叉,它起作用了:
- (void)setPlaces:(NSArray *)places
{
if(_places != places)
{
_places = [places sortedArrayUsingComparator:^(id a, id b){
NSString *first = [a objectForKey:FLICKR_PLACE_NAME];
NSString *second = [b objectForKey:FLICKR_PLACE_NAME];
return [first caseInsensitiveCompare:second];
}
];
if (self.tableView.window) [self.tableView reloadData];
} //if _places
} //set