我需要创建多个状态栏通知。当我拉下状态栏时,应该将多个通知图标显示为列表。每个通知图标都应显示下一页显示的单独数据。我该怎么做?
我的代码:
public class SimpleNotification extends Activity {
private NotificationManager mNotificationManager;
private int SIMPLE_NOTFICATION_ID;
String str="Hai";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
mNotificationManager = (NotificationManager)getSystemService(NOTIFICATION_SERVICE);
final Notification notifyDetails = new Notification(R.drawable.android,"New Alert, Click Me!",System.currentTimeMillis());
Button start = (Button)findViewById(R.id.notifyButton);
Button cancel = (Button)findViewById(R.id.cancelButton);
start.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
Context context = getApplicationContext();
CharSequence contentTitle = "Notification Details...";
CharSequence contentText = "Browse Android Official Site by clicking me";
Intent notifyIntent = new Intent(SimpleNotification.this,
sub.class);
Bundle bundle = new Bundle();
bundle.putString("welcome",str);
notifyIntent.putExtras(bundle);
PendingIntent intent =
PendingIntent.getActivity(SimpleNotification.this, 0,
notifyIntent, android.content.Intent.FLAG_ACTIVITY_NEW_TASK);
notifyDetails.setLatestEventInfo(context, contentTitle, contentText, intent);
mNotificationManager.notify(SIMPLE_NOTFICATION_ID, notifyDetails);
}
});
我在这里做过一次通知,但我需要创建多个通知,每个通知应该显示每个数据。
答案 0 :(得分:29)
您需要为每个通知传递唯一ID。点击通知后,您可以使用该ID将其删除。
public class SimpleNotification extends Activity {
private NotificationManager mNotificationManager;
private int SIMPLE_NOTFICATION_ID_A = 0;
private int SIMPLE_NOTFICATION_ID_B = 1;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
mNotificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
Button start = (Button) findViewById(R.id.start_button);
start.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
// display A
displayNotification("Extra for A", "This is A", "Some text for activity A", MyActivityA.class, SIMPLE_NOTFICATION_ID_A);
// display B
displayNotification("Extra for B", "This is B", "Some text for activity B", MyActivityB.class, SIMPLE_NOTFICATION_ID_B);
}
});
}
private void displayNotification(String extra, String contentTitle, String contentText, Class<?> cls, int id) {
Notification notifyDetails = new Notification(R.drawable.icon, "New Alert!", System.currentTimeMillis());
Intent intent = new Intent(this, cls);
intent.putExtra("extra", extra);
PendingIntent contentIntent = PendingIntent.getActivity(getApplicationContext(), id, intent, PendingIntent.FLAG_ONE_SHOT);
notifyDetails.setLatestEventInfo(getApplicationContext(), contentTitle, contentText, contentIntent);
mNotificationManager.notify(id, notifyDetails);
}
}
MyActivityA - 在onCreate()
中...
mNotificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
mNotificationManager.cancel(SIMPLE_NOTFICATION_ID_A);
...
答案 1 :(得分:7)
只需在mNotificationManager.notify(ID, notifyDetails);
如果您重复使用该ID,则不会添加新ID,而是更新旧版本。
以下是有关如何使用notifications的指南。
答案 2 :(得分:2)
你必须使用 notfication id ,因为有时候解决方案是你必须使用 ramdom 强>数字概念
Random random = new Random();
int randomNumber = random.nextInt(9999 - 1000) + 1000;
notificationManager.notify(randomNumber, notification);
答案 3 :(得分:1)
This example显示了如何创建多个通知
答案 4 :(得分:0)
如果要在每个通知上显示不同的数据。使用待审FLAG_UPDATE_CURRENT
中的举报Intent
。
PendingIntent contentIntent = PendingIntent.getActivity(this, 0, intent, PendingIntent.FLAG_UPDATE_CURRENT);
它会更新每个通知的数据,而不必每次都重新创建。