Question

您好我喜欢构建一个字符串函数：

if member of a list of string: 
    "Nissan" from "Honda, Toyota, Nissan, Mazda"

  if start with or end with
    "Nissan" from "Nis*" as start with 
    "Nissan" from "*san" as end with

  if not start with or end with 
    "Ford" from "^Nis*" as start with 
    "Ford" from "^*san" as end with 

  if Not member of a list of string:
    "Ford" from "^Hon*, ^Toy*, Nis*, Mazda"

我认为Regex可能是解决方案，但我是如何实现的？

谢谢韦斯

Answer 1

很难理解你的要求，但我会尽力猜测：

检查字符串是否为以下之一：Honda, Toyota, Nissan, Mazda

^(Honda|Toyota|Nissan|Mazda)$
以Nis
开头
```
^Nis.*$
```
以san
结束
```
^.*san$
```
不以Nis
开头
```
^(?!Nis).*
```
不以san
结尾
```
^.*(?<!san)$
```
不包含任何Hon*, Toy*, Nis*, Mazda
```
^(?!Hon.*|Toy.*|Nis.*|Mazda).*
```

Answer 2

不完全确定你在问什么，但是

如果你有

List<string> strings = ...

和

string input = ...

然后你可以做

bool memberIsInList = strings.Contains(input);      
bool memberStartsOrEndsWith = strins.Any(s => s.StartsWith(input) || s.EndsWith(input));

对于其他两个应该是相似的，在not运算符（!）

中混合

字符串匹配功能

2 个答案: