Question

编辑：我想删除结构类型的数组列表中的元素之一

struct Folder {
  let name:String
  let menu:[String:String]
}

我有一个变量

section = Folder

我想检查菜单中是否有任何值[String：String]是否包含特定值，然后将该元素删除

section.menu = ["hello" : "a","b","c"]
if there any value of hello == a {
    remove it out
}

最后

section.menu = ["hello" : "b","c"]

Answer 1

因此，首先您需要使menu成为实际变量而不是常量，并且它必须是从Strings到String Array的字典。

然后，您可以通过获取它们的索引并调用remove来轻松地从数组中删除条目：

struct Folder {
    let name:String
    var menu: [String: [String]]
}

var section = Folder(name: "foo", menu: [ "hello": ["a", "b", "c"]])

if let index = section.menu["hello"]?.firstIndex(of: "a") {
    section.menu["hello"]?.remove(at: index)
}

print(section.menu) // ["hello": ["b", "c"]]

Answer 2

您可以创建mutating之类的removeMenu(forValue value: String)函数

struct Folder {
    let name:String
    var menu:[String:String]

    mutating func removeMenu(forValue value: String) {
        menu = menu.filter({ $0.value != value})
    }
}

var section = Folder(name: "FolderName", menu: ["k1": "keyValue1", "k2": "keyValue2"])

section.removeMenu(forValue: "keyValue1")

print(section)

输出：

//Folder(name: "FolderName", menu: ["k2": "keyValue2"])

快速删除结构数组中的元素

2 个答案: