我正在尝试打印.csv文件的行号,但它仅输出所有行上的最后一个行号,这是我的代码:
import csv
openfile = open('example_csv.csv')
readcsv = csv.reader(openfile, delimiter = ',')
list_csv_content = list(readcsv)
for row in list_csv_content:
print(f'Row #{readcsv.line_num} {row}')
输出如下:
Row #7 ['4/5/2015 13:34', 'Apples', '73']
Row #7 ['4/5/2015 3:41', 'Cherries', '85']
Row #7 ['4/6/2015 12:46', 'Pears', '14']
Row #7 ['4/8/2015 8:59', 'Oranges', '52']
Row #7 ['4/10/2015 2:07', 'Apples', '152']
Row #7 ['4/10/2015 18:10', 'Bananas', '23']
Row #7 ['4/10/2015 2:40', 'Strawberries', '98']
我在做什么错?
答案 0 :(得分:1)
line_num
属性只是您的阅读器读取的总行数。
但是,以下代码应该可以工作,enumerate
在您获得实际行的地方,以及该行的从零开始的索引。
import csv
openfile = open('chart-images.csv')
readcsv = csv.reader(openfile, delimiter = ',')
list_csv_content = list(readcsv)
for line_num, row in enumerate(list_csv_content):
print(f'Row #{line_num} {row}')
答案 1 :(得分:1)
将readcsv
保存到列表中时,您正在读取整个csv,这就是line_num指向最后一行的原因。
您可以通过不将csv保存到列表中来解决此问题:
openfile = open('test.csv')
readcsv = csv.reader(openfile, delimiter = ',')
for line in readcsv:
print(line, readcsv.line_num)
或通过列举列表:
import csv
openfile = open('example_csv.csv')
readcsv = csv.reader(openfile, delimiter = ',')
list_csv_content = list(readcsv)
for i, row in enumerate(list_csv_content):
print(f'Row #{i} {row}')