我有一张桌子Managers
。专栏:ManagerId, ManagerName
。
我有一张桌子Clients
。专栏:ClientId, ManagerId, ClientName, ClientAddress, Details
。
每个(每个?)经理在客户表中都有客户。
我需要一个返回下一个表的查询。列:Column1,Column2。
第1列:ManagerName
第2栏:ClientName1 ',' ClientAddress1 ',' Details1 ';' ClientName2 ',' ClientAddress2 ',' Details2 ';' etc
在column2中只是一个与column1中的manager相对应的客户端列表。
我该怎么做?
我想我需要使用COALESCE,但我不确定。
答案 0 :(得分:2)
与之前的答案相同,只是处理空值和XML特殊字符<>&'"
。
declare @Managers table
(
ManagerId int,
ManagerName varchar(50)
)
declare @Clients table
(
ClientId int,
ManagerId int,
ClientName varchar(50),
ClientAddress varchar(50),
Details varchar(50)
)
insert into @Managers values(1, 'Manager 1')
insert into @Managers values(2, 'Manager 2')
insert into @Clients values (1, 1, 'Client 1', 'CA 1', 'D 1')
insert into @Clients values (2, 1, 'Client 2', 'CA 2', 'D 2')
insert into @Clients values (3, 2, 'XML special characters &<>" and null values', null, 'D 3')
select M.ManagerName,
stuff((select '; '+
coalesce(C.ClientName, '')+', '+
coalesce(C.ClientAddress, '')+', '+
coalesce(C.Details, '')
from @Clients as C
where C.ManagerId = M.ManagerId
for xml path(''), type).value('.', 'nvarchar(max)'), 1, 2, '') as Clients
from @Managers as M
结果:
ManagerName Clients
----------- ---------------------------------------------------
Manager 1 Client 1, CA 1, D 1; Client 2, CA 2, D 2
Manager 2 XML special characters &<>" and null values, , D 3
答案 1 :(得分:1)
以下是使用XML AUTO
With Managers AS
(
Select 1 as ManagerId, 'Tom' as ManagerName
UNION Select 2 as ManagerId, 'Jane' as ManagerName
),
Clients as
(
Select 1 as ClientId, 1 as ManagerId, 'TaXon Pro' as ClientName, '112 Acme St Cityville DD 56' as ClientAddress, 'ABC' as Details
UNION Select 2 as ClientId, 1 as ManagerId, 'Pro Xon' as ClientName, '12342 Bylo Rd Streetville DD 156' as ClientAddress, 'CDR' as Details
UNION Select 3 as ClientId, 1 as ManagerId, 'Clean Svc' as ClientName, '6512 Toni St Townville DD 1236' as ClientAddress, 'D@#$' as Details
UNION Select 4 as ClientId, 2 as ManagerId, 'ContraRel' as ClientName, '152 Acme St Villageville DD 3456' as ClientAddress, 'SER' as Details
UNION Select 5 as ClientId, 2 as ManagerId, 'RepoIn' as ClientName, '1 Acme St Districtville DD 1456' as ClientAddress, 'KH' as Details
)
SELECT
M.ManagerName,
(
SELECT c.ClientName + ', ' + C.ClientAddress + ', ' + c.Details + ';'
FROM Clients C
WHERE m.ManagerId = c.ManagerId
FOR XML PATH('')
) AS Clients
FROM Managers M
GROUP BY
m.ManagerId, M.ManagerName
输出将如下所示
ManagerName Clients
----------- -------------------------------------------------------------------------------------------------------------------------------------------
Tom TaXon Pro, 112 Acme St Cityville DD 56, ABC;Pro Xon, 12342 Bylo Rd Streetville DD 156, CDR;Clean Svc, 6512 Toni St Townville DD 1236, D@#$;
Jane ContraRel, 152 Acme St Villageville DD 3456, SER;RepoIn, 1 Acme St Districtville DD 1456, KH;
(2 row(s) affected)
答案 2 :(得分:1)
SELECT
ManagerName,
(
SELECT ClientName + ', ' + ClientAddress + ', ' + Details + ' ; '
FROM Clients c
WHERE c.ManagerId = m.ManagerId
FOR XML PATH ('')
) AS clients
FROM Managers m