Question

我正在尝试清除我从API请求的JSON，因为数据库插入了键名，键值结构并使所有内容混乱，但是不幸的是我无法使用背面，所以我必须清除JSON在前面，问题之一是数据不一定总是相同的结构，因此，我需要一个递归解决方案来迭代所有嵌套的JSON，真正的JSON具有更多的嵌套子对象，但是出于演示目的，我仅展示JSON的一部分。

这是结构的一个示例，但有时结构不相同，有时我没有得到总体或总体值之一。

def reverse(l):
            t=""
            for i in range(len(l)):
                if(l[i]=='A'):
                    t=t+'T'
                elif(l[i]=='T'):
                    t=t+'A'
                elif(l[i]=='C'):
                    t=t+'G'
                elif(l[i]=='G'):
                    t=t+'C'
            return t
        def rev(d):
            return d[len(d)::-1]
        k=input()
        p=input()
        for i in range(len(p)):
            for j in range(4,14):
                if (p[i:i+j]==rev(reverse(p[i:i+j]))and i+j<=len(p)):
                    print(i+1, end=" ")
                    print(j)

我正在尝试清除所有键名，键值，以获得类似这样的内容：

[
  { "Name": "code", "Value": "18187" },
  { "Name": "date", "Value": "2020-05-10" },
  {
    "Name": "countries",
    "Value": [
      [
        { "Name": "id", "Value": "1" },
        { "Name": "name", "Value": "Canada" },
        {
          "Name": "population",
          "Value": [
            [
              { "Name": "id", "Value": "1" },
              { "Name": "male", "Value": "1000" }
            ],
            [
              { "Name": "id", "Value": "2" },
              { "Name": "female", "Value": "1000" }
            ]
          ]
        }
      ],
      [
        { "Name": "id", "Value": "2" },
        { "Name": "name", "Value": "Italy" },
        {
          "Name": "population",
          "Value": [
            [
              { "Name": "id", "Value": "1" },
              { "Name": "male", "Value": "1000" }
            ],
            [
              { "Name": "id", "Value": "2" },
              { "Name": "female", "Value": "1000" }
            ]
          ]
        }
      ]
    ]
  }
]

Answer 1

您可以使用使用map方法的递归函数。

const data = [{"Name":"code","Value":"18187"},{"Name":"date","Value":"2020-05-10"},{"Name":"countries","Value":[[{"Name":"id","Value":"1"},{"Name":"name","Value":"Canada"},{"Name":"population","Value":[[{"Name":"id","Value":"1"},{"Name":"male","Value":"1000"}],[{"Name":"id","Value":"2"},{"Name":"female","Value":"1000"}]]}],[{"Name":"id","Value":"2"},{"Name":"name","Value":"Italy"},{"Name":"population","Value":[[{"Name":"id","Value":"1"},{"Name":"male","Value":"1000"}],[{"Name":"id","Value":"2"},{"Name":"female","Value":"1000"}]]}]]}]

function modify(data) {
  return data.map(e => {
    if (Array.isArray(e)) return modify(e)
    else {
      const { Name, Value } = e;
      return ({
        [Name]: Array.isArray(Value) ?
          modify(Value) : Value
      })
    }
  })
}

const result = modify(data);
console.log(result)

将键名称更改为嵌套JSON的键值结构

1 个答案: