Question

我需要使用POST方法获取基于SECRET CODE的json数据响应，请先解决我的问题，

使用secret code的POST方法获取JSON响应时，我遇到了很多问题

 public class MainActivity extends AppCompatActivity {
ListView listView;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    listView = (ListView) findViewById(R.id.listViewHeroes);


    getQuestions();
}

private void getQuestions() {
    Retrofit retrofit = new Retrofit.Builder()
            .baseUrl(ApiInterface.BASE_URL)
            .addConverterFactory(GsonConverterFactory.create()) //Here we are using the GsonConverterFactory to directly convert json data to object
            .build();

    ApiInterface api = retrofit.create(ApiInterface.class);

    RequestModel requestModel = new RequestModel();
    requestModel.setSecretCode("341977082");

    Call<List<ModelObjects>> call = api.getQuestions();

   call.enqueue(new Callback<List<ModelObjects>>() {
       @Override
       public void onResponse(Call<List<ModelObjects>> call, Response<List<ModelObjects>> response) {
           List<ModelObjects> questionsList = response.body();


           String[] questions = new String[questionsList.size()];


           for (int i = 0; i < questionsList.size(); i++) {
               questions[i] = questionsList.get(i).getQues_No();
           }



           listView.setAdapter(new ArrayAdapter<String>(getApplicationContext(), android.R.layout.simple_list_item_1, questions));
       }

       @Override
       public void onFailure(Call<List<ModelObjects>> call, Throwable t) {
           Toast.makeText(getApplicationContext(), t.getMessage(), Toast.LENGTH_SHORT).show();
       }
   });}}

这是界面，我在其中传递包含父项和扩展名的URL

public interface ApiInterface {

String BASE_URL = "";

@POST("QuestionsList")
Call<List<ModelObjects>> getQuestions();}

这是响应模型

 public class ModelObjects {
@SerializedName("Ques_No")
private String Ques_No;

public ModelObjects(String ques_No) {
    Ques_No = ques_No;
}

public String getQues_No() {
    return Ques_No;
}

public void setQues_No(String ques_No) {
    Ques_No = ques_No;
}}

这是请求模型

 public class RequestModel {
private String SecretCode;

public RequestModel(String secretCode) {
    SecretCode = secretCode;
}

public RequestModel() {

}

public String getSecretCode() {
    return SecretCode;
}

public void setSecretCode(String secretCode) {
    SecretCode = secretCode;
}}

Answer 1

此处您已定义RequestModel，但没有将其传递给api调用。发布请求应具有正文。因此，在定义如下所示的api调用时，请指定@Body。

@POST("QuestionsList")
Call<List<ModelObjects>> getQuestions(@Body RequestModel model);

然后在调用getQuestion()时传递模型。

RequestModel requestModel = new RequestModel();
requestModel.setSecretCode("341977082");
Call<List<ModelObjects>> call = api.getQuestions(requestModel);

更新：如下更新您的ModelObject。

public class ModelObjects {
@SerializedName("Ques_No")
String Ques_No;
@SerializedName("Question")
String Ques;
@SerializedName("Answer")
String answer;
//same for other params as well
}

Answer 2

我能看到什么，您正在创建RequestModel类的对象，但没有将它传递到任何地方。如果要与网络发布后的呼叫一起发送secretCode，则必须将此requestModel实例传递给该呼叫。

    public interface ApiInterface {
    String BASE_URL = "";
    @POST("QuestionsList")
    Call<List<ModelObjects>> getQuestions(@Body RequestModel requestModel);
    }

然后您可以调用此方法并可以通过以下方式传递此requestModel对象

    Call<List<ModelObjects>> call = api.getQuestions(requestModel);

如果要访问第一个对象，可以通过

   List<ModelObjects> questionsList = response.body();
   ModelObject obj = questionList.get(0);
   String question = obj.getQues_No();

这个问题将是第一个问题。

如何在Android Studio中通过带有秘密代码的POST方法获取JSON数据

2 个答案: